至少有两种方法可以实现这一点 -
1) 使用 RxJava Zip 运算符(用于并行请求)
获取所有可观察对象
Observable<ResponseType1> observable1 = retrofit.getApi_a();
Observable<ResponseType2> observable2 = retrofit.getApi_b();
Observable<ResponseType3> observable3 = retrofit.getApi_c();
压缩 observables 以获得最终的 observable
Observable<List<String>> result =
Observable.zip(observable1.subscribeOn(Schedulers.io()), observable2.subscribeOn(Schedulers
.io()), observable3.subscribeOn(Schedulers.io()), new Function3<ResponseType1, ResponseType2, ResponseType3, List<String>>() {
@Override
public List<String> apply(ResponseType1 type1, ResponseType2 type2, ResponseType3 type3) {
List<String> list = new ArrayList();
list.add(type1.data);
list.add(type2.data);
list.add(type3.data);
return list;
}
});
现在订阅结果 observable
result.observeOn(AndroidSchedulers.mainThread())
.subscribeWith(new Observer<List<String>>() {
@Override
public void onSubscribe(Disposable d) {
}
@Override
public void onNext(List<String> s) {
Log.d(TAG, "s is the list with all the data");
}
@Override
public void onError(Throwable e) {
Log.e(TAG, e.getMessage());
}
@Override
public void onComplete() {
}
});
2) 使用 RxJava flatMap() 操作符。(依次请求)
这是简单的请求链接
List<String> result = new ArrayList<>();
Disposable disposable = retrofit.getApi_a()
.subscribeOn(Schedulers.io())
.flatMap((Function<ResponseType1, ObservableSource<ResponseType2>>) response1 -> {
result.add(response1.data);
return retrofit.getApi_b();
})
.flatMap((Function<ResponseType2, ObservableSource<ResponseType3>>) response2 -> {
result.add(response2.data);
return retrofit.getApi_c();
})
.map(response3 -> {
result.add(response3.data);
return response3;
})
.observeOn(AndroidSchedulers.mainThread())
.subscribeWith(new DisposableObserver<Response3>() {
@Override
public void onNext(Response3 response3) {
Log.d(TAG, "result variable will have all the data");
}
@Override
public void onError(Throwable e) {
Log.e(TAG, e.getMessage());
}
@Override
public void onComplete() {
}
});