在Android中通过文件（使用FileInputStream）将图像发送到PHP并通过Blob保存mysql

Question

I'm trying to send an image converted by file and fileinputstream with my android app for my PHP server and then save it in BLOB field in MySQL DB, but I tried too many things, but nothing is ok. What can I do? And so, is this possible? Help, please!

我的 PHP 服务器接收到 json 并像往常一样保存其他字段，但图像没有像使用 java NetBeans 那样保存在 blob 字段中。

public void cadastrarTAG(ModeloTAG tag) throws JSONException {

    FileWriter writeFile = null;

    JSONObject json = new JSONObject();

    json.put("tag", String.valueOf(tag.getTag()));
    json.put("equipamento", String.valueOf(tag.getEquipamento()));
    json.put("data_registro", String.valueOf(tag.getData_registro()));
    json.put("login", String.valueOf(tag.getLogin()));
    json.put("descricao", String.valueOf(tag.getDescricao()));
    json.put("obs", String.valueOf(tag.getObs()));
    json.put("total_manutencoes", 0);
    json.put("setor", String.valueOf(tag.getSetor()));
    json.put("imagemFileLength", tag.getFile().length()); Field file length
    json.put("imagemFIS", tag.getFis()); field fileinputstream


    try {
        writeFile = new FileWriter(new File(android.os.Environment.getExternalStorageDirectory(), "saida.json"));
        writeFile.write((json.toString()));
        writeFile.flush();
        writeFile.close();

    } catch(Exception e){
        System.err.println("ERRO-> "+e);
        //e.printStackTrace();
    }

    try {
        log.geraLog("Cadastro de TAG ("+tag.getSetor()+") (MOBILE)", "PINS", (String) Login.rotinas[1], md.getDataHora());
        enviaJson.enviaJsonGravar(arquivoPHP, json);
    } catch (Exception e) {
        e.printStackTrace();
    }

}

我的 PHP 服务器接收到 json 并像往常一样保存其他字段，但图像没有像使用 java NetBeans 那样保存在 blob 字段中。

Answer 1

public function salvaImagem($conn, $json, $cod) {
          $flag['code'] = 0;
            echo "imagemFileLength 3 ---->>>>> ".$json->{'imagemFileLength'};
            echo "imagemFIS 3 ---->>>>> ".$json->{'imagemFIS'};

            $stmt = $conn->prepare("update tag set imagem = ? where id = ".$cod." and login = '{$json->{'login'}}'");
            $imageContent = fread($json->{'imagemFIS'}, filesize($json->{'imagemFileLength'}));
            //$imageContent = mysqli_real_escape_string($conn, $imageContent);
            //$stmt->bind_param('s',  mysql_real_escape_string($conn, $json->{'imagemFIS'}));
            $stmt->bind_param('s',  $imageContent);
            //$stmt->bindValue(1, $json->{'imagemFIS'});
            $stmt->execute();

            if ($stmt->execute()) {
              echo "New record created successfully";
            } else {
              echo "Unable to create record";


            $stmt->close();
            $conn->close();
        }

Answer 2

我想您正试图通过调用json.put("imagemFIS", tag.getFis()); 将图像放入 json 中。

它只是将FileInputStream 对象写入json。 您可能应该尝试将图像读取到 byte[]，将其转换为 Base64 编码的 String，然后将其放入您的 json 中。

另外，最好将图像文件的路径或 URI 保留为 String 在您的 ModeloTAG 对象中而不是 FileInputStream，即：

public void cadastrarTAG(ModeloTAG tag) throws JSONException {
    ...
    /* read bytes */
    try {
        final byte[] fileBytes = getFileBytes(new File(tag.getPath));
        json.put("image", Base64.encodeToString(fileBytes, Base64.DEFAULT));
    } catch (FileNotFoundException e) {
        // Handle the exception
    } catch (IOException e) {
        // Handle the exception
    }
    ...
}

private byte[] getFileBytes(final String path) throw IOException, FileNotFoundException {
    final FileInputStream fis = new FileInputStream(new File(path));
    final ByteArrayOutputStream bos = new ByteArrayOutputStream();

    final byte[] buffer = new byte[2048];

    int read = 0;

    while ((read = fis.read(buffer, 0, buffer.length)) > 0) {
        bos.write(buffer, 0, read);
    }

    fis.close();

    return bos.toByteArray();
}

在您的后端，您只需要解码 Base64 编码的字符串并将其保存为 blob 或原样保存。

希望有帮助！

Answer 3

The problem is solved, I fix by sending imageview converted in Base64 for my PHP server and converting it into blob with this method.

public function salvaImagem($conn, $json, $cod) {
          $flag['code'] = 0;
            $blobData = base64_decode($json->{'imagem64'}); /* BASE64_DECODE and saving it like String with bind_param */
            $stmt = $conn->prepare("update tag set imagem = ? where id = ".$cod." and login = '{$json->{'login'}}'");
            $stmt->bind_param('s',  $blobData);
            $stmt->execute();

            if ($stmt->execute()) {
              echo "New record created successfully";
            } else {
              echo "Unable to create record";


            $stmt->close();
            $conn->close();
        }