如何使用android捕获图像并存储在服务器上答案

【问题标题】：How to capture an image and store on server using android如何使用android捕获图像并存储在服务器上
【发布时间】：2011-06-26 19:35:47
【问题描述】：

我正在尝试将图像从 Android 设备上传到远程服务器。到目前为止，我有以下代码，但保存在远程服务器上的图像始终为零字节。

     HttpURLConnection conn;

     String serverpath = "http://110.172.27.47:9499";
     String MREPORTER_SERVLET_PATH="/mreporter/servlet/MReporterServlet";


     url = serverpath + MREPORTER_SERVLET_PATH;

     try
     {
         URL url = new URL( serverpath + MREPORTER_SERVLET_PATH );
         conn = (HttpURLConnection) url.openConnection();
         conn.setDoInput(true);
         conn.setDoOutput(true);
         conn.setUseCaches(false);

         conn.setRequestMethod("POST");

         conn.setRequestProperty("Connection", "Keep-Alive"); 
         conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+ "*****" );

         conn.setRequestProperty(USER_NAME_REQUEST_PARAMETER, "parth");
         conn.setRequestProperty(EVENT_NAME_REQUEST_PARAMETER, "null" );
         conn.setRequestProperty(CAMERAID_REQUEST_PARAMETER, "1");
         conn.setRequestProperty(ACTION_MODE_PARAMETER, "POST_DATA_ACTION" );

         DataOutputStream dos = new DataOutputStream(conn.getOutputStream());

         Log.i("Response", conn.getResponseCode() + "" );

         int response = conn.getResponseCode();

         if ( response == 200 )
         {
             Log.i("size",data.length + "");

             if ( data.length > 0 )
             {
                 dos.write(data);
                 Log.i("200","OK" );
             }
             else
             {
                 Log.i( "Error", response +  "" );
             }
         }

【问题讨论】：

标签： android image-uploading

【解决方案1】：

我查看了代码并在这里找到了解决方案，它确实有效。

     HttpURLConnection conn;
     String serverpath = "http://110.172.27.47:9499";
     String MREPORTER_SERVLET_PATH="/mreporter/servlet/MReporterServlet";


     url = serverpath + MREPORTER_SERVLET_PATH;

     try
     {
         URL url = new URL( serverpath + MREPORTER_SERVLET_PATH );
         conn = (HttpURLConnection) url.openConnection();
         conn.setDoInput(true);
         conn.setDoOutput(true);
         conn.setUseCaches(false);

         conn.setRequestMethod("POST");

         conn.setRequestProperty("Connection", "Keep-Alive"); 
         conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+ "*****" );

         conn.setRequestProperty(USER_NAME_REQUEST_PARAMETER, "parth");
         conn.setRequestProperty(EVENT_NAME_REQUEST_PARAMETER, "null" );
         conn.setRequestProperty(CAMERAID_REQUEST_PARAMETER, "1");
         conn.setRequestProperty(ACTION_MODE_PARAMETER, "POST_DATA_ACTION" );

         DataOutputStream dos = new DataOutputStream(conn.getOutputStream());

         Log.i("Response", conn.getResponseCode() + "" );

         int response = conn.getResponseCode();
         dos.write(data);
}

【讨论】：

不要把你的回答作为评论给出适当的规范（如果你知道的话），这样它对其他人也有用

【解决方案2】：

我认为这个example 可以帮助你。

【讨论】：