如何在运行时允许用户创建新的 Picturebox Visual Studio C# Windows Forms Apps答案

【问题标题】：How to at runtime allow a user to create a new Picturebox Visual Studio C# Windows Forms Apps如何在运行时允许用户创建新的 Picturebox Visual Studio C# Windows Forms Apps
【发布时间】：2021-07-12 09:42:32
【问题描述】：

我正在尝试在 Visual Studio Windows Forms Apps C# 中创建一个窗体，在该窗体中，用户或操作员可以在运行时通过单击鼠标左键创建一个新的图片框，然后能够移动创建的每个图片框。

我真的不知道从哪里开始。有人有什么想法吗？

【问题讨论】：

标签： c# visual-studio mouseevent picturebox windows-forms-designer

【解决方案1】：

要动态添加新的 PictureBox，您可以订阅事件Form_MouseClick 并像这样创建 PictureBox：

public Form1()
{
    InitializeComponent();
    this.MouseClick += Form_MouseClick;
}

private void Form_MouseClick(object sender, MouseEventArgs e)
{
    PictureBox pictureBox = new PictureBox();
    // cursor location
    pictureBox.Location = new Point(e.X, e.Y);
    pictureBox.BackColor = Color.Red;
    this.Controls.Add(pictureBox);
}

要拖动和移动图片框，您还需要订阅MouseDown、MouseUp和MouseMove事件。

这是一个简单的演示，您可以参考。

private void Form_MouseClick(object sender, MouseEventArgs e)
{
    // create new control
    PictureBox pictureBox = new PictureBox();
    pictureBox.Location = new Point(e.X, e.Y);
    pictureBox.BackColor = Color.Red;
    this.Controls.Add(pictureBox);
    // bind event for each PictureBox
    pictureBox.MouseDown += pictureBox_MouseDown;
    pictureBox.MouseUp += pictureBox_MouseUp;
    pictureBox.MouseMove += pictureBox_MouseMove;
}


Point mouseDownPoint = Point.Empty;
Rectangle rect = Rectangle.Empty;
bool isDrag = false;

private void pictureBox_MouseDown(object sender, MouseEventArgs e)
{
    if (e.Button == MouseButtons.Left)
    {
        mouseDownPoint = e.Location;
        rect = (sender as PictureBox).Bounds;
    }
}

private void pictureBox_MouseUp(object sender, MouseEventArgs e)
{
    if (e.Button == MouseButtons.Left)
    {
        if (isDrag)
        {
            isDrag = false;
            (sender as PictureBox).Location = rect.Location;
            this.Refresh();
        }
        reset();
    }
}

private void pictureBox_MouseMove(object sender, MouseEventArgs e)
{
    if (e.Button == MouseButtons.Left)
    {
        isDrag = true;
        rect.Location = this.PointToClient((sender as PictureBox).PointToScreen(new Point(e.Location.X - mouseDownPoint.X, e.Location.Y - mouseDownPoint.Y)));
        this.Refresh();
    }
}

private void reset()
{
    mouseDownPoint = Point.Empty;
    rect = Rectangle.Empty;
    isDrag = false;
}

【讨论】：

非常彻底和好的回复，非常感谢。需要时间来整理一下，但这看起来很有希望！会尽快回复您。
太棒了。你完美地回答了这个问题。干杯@Kyle Wang。

【解决方案2】：

您可以在运行时添加表单元素：

var picture = new PictureBox
{
    Name = "pictureBox",
    Size = new Size(16, 16),
    Location = new Point(100, 100),
    Image = Image.FromFile("test.jpg"),

};
this.Controls.Add(picture);

之后，您可以使用鼠标事件移动它

【讨论】：