【问题标题】:how to list all the files of a custom directory如何列出自定义目录的所有文件
【发布时间】:2018-11-10 21:47:56
【问题描述】:

我想让用户从列表中选择一个 courseName 并显示该目录下的所有文件,我该如何实现?我正在努力寻找一种方法来显示特定课程的所有文件。 这是我到目前为止所做的:

views.py

def showDocuments(request):
    if request.POST:
    if Document.objects.filter(courses__exact=request.POST["course"]).exists():
        print(request.POST["course"])
    else:
        print("there is no files for this course yet!")

    documents = Document.objects.all()
    courses = Course.objects.all()
    context = {
        "documents" : documents ,
        "courses" : courses,
    }
    return render(request , 'dashboard.html' , context )

models.py

class Document(models.Model):
    #to do : enum class ! 
    DB = "data structure"
    SF = "software enginering"
    DS = "discrete structure " 
    WD = "web dev"
    OPTIONS = "options"
    courseChoices = (
        (DB , "data structure"),
        (SF , "software enginering "),
        (DS , "discrete structure"),
        (WD , "web dev"),
        (OPTIONS , "options"),
    )
    courses     = models.CharField(max_length=50, choices=courseChoices, default=OPTIONS)
    description = models.TextField(help_text="A little description can be very helpful for others!")
    document    = models.FileField(upload_to=content_file_name)
    uploaded_at = models.DateTimeField(auto_now_add=True)

    def __str__(self):
        return "{}".format(self.document)

    def content_file_name(self, courses):
        file_path = "documents/{courses}/{filename}".format(
            courses=self.courses, filename=courses)
        return file_path

dashboard.html

<div class="col-sm-4">
       <select id="crs" class="custom-select custom-select-sm" name="course">
          <option selected>option</option>
          {% for obj in courses %}
                    <option value="{{ obj.courseName }}">{{ obj.courseName }}</option>
            {% endfor %}
        </select>
    </div>

【问题讨论】:

  • 您的showDocuments 是否有额外的参数(课程名称)?
  • @WillemVanOnsem 据我所知,我应该以某种方式使用 request.post[] 从用户那里获取它?
  • 是的,这是一种可能性(尽管通常用于搜索的人使用GET,因为这样就可以共享搜索 URL)。 &lt;input name="..."&gt; 元素的名称是什么(所以映射到要搜索的元素的键)?
  • @WillemVanOnsem 我刚刚更新了我的问题,请看一下。

标签: django python-3.x django-models django-forms


【解决方案1】:

所以这是我的解决方案:

def showDocuments(request, *args, **kwargs):
    """ shows all the files of the requested course  """
    crs_names = CoursesNames.objects.all()
    context = {
        "crs_names": crs_names,
        "files": [],
        "not_found" : "",
    }
    if request.POST:

        file_name = request.POST["course"]
        not_found = "There are no files for {0} yet!".format(file_name)
        documents = Document.objects.all().filter(course_name__courses__iexact=file_name)
        context["documents"] = documents
        context["filename"] = file_name

        documentObjectList = Document.objects.all().values_list("document").filter(course_name__courses__iexact=file_name)
        queryset = CoursesNames.objects.filter(courses__exact=file_name).exists()

        if queryset:
            while len(context["files"]) > 0: context["files"].pop()
            for i in documentObjectList:
                context["files"] = i
                print(context["files"])
            if len(context["documents"]) == 0: context["not_found"] = not_found
    return render(request, 'dashboard.html', context)

【讨论】:

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