【发布时间】:2018-02-14 03:14:38
【问题描述】:
因此,我被分配为我的编程课编写一个程序,该程序会提示用户并将输入的值读取为双精度值(最大输入为 [99.99] 九十九美元和九十九美分),这将代表一个货币金额。然后,我将确定代表所述金额所需的每张钞票和硬币的最少数量(10 美元钞票是所需的最大尺寸)。
我遇到了四舍五入的问题。例如,输入 99.99 将返回 3 便士,而它应该是 4 便士。我的老师明确告诉我不要超出课堂上所涵盖的材料(仅限于创建扫描仪、转换数据类型和强制转换。这意味着没有 BigDecimal)。任何帮助将不胜感激。
import java.util.Scanner;
public class MoneyConversion
{
public static void main(String[] args)
{
//Set variables for input, dollars, and cents
double inputAmount, change;
int tens, fives, ones;
int quarters, dimes, nickels, pennies;
//Create scanner to setup for user input
Scanner scan = new Scanner(System.in);
//Scan user input and store into double
System.out.print("Enter monetary amount: ");
inputAmount = scan.nextDouble();
//Extract demical or cent amount from dollar amount
change = (inputAmount - (int) inputAmount) * 100;
System.out.println("That's equivalent to:");
//Extract and print denomination for ten-dollar bills
tens = (int) inputAmount / 10;
inputAmount = inputAmount % 10;
System.out.println(tens + " ten dollar bills");
//Extract and print denomination for five-dollar bills
fives = (int) inputAmount / 5;
inputAmount = inputAmount % 5;
System.out.println(fives + " five dollar bills");
//Extract and print denomination for one-dollar bills
ones = (int) inputAmount;
System.out.println(ones + " one dollar bills");
//Extract and print denomination for quarters
quarters = (int) change / 25;
change = change % 25;
System.out.println(quarters + " quarters");
//Extract and print denomination for dimes
dimes = (int) change / 10;
change = change % 10;
System.out.println(dimes + " dimes");
//Extract and print denomination for nickels
nickels = (int) change / 5;
change = change % 5;
System.out.println(nickels + " nickels");
//Convert value for change to integer value and print for pennies
pennies = (int) change;
System.out.println(pennies + " pennies");
}
}
【问题讨论】:
-
我总是使用整数来计算金钱。将值表示为美分。 100 就是 1 美元。
-
谢谢!我继续,只是将 inputAmount 变量转换为美分,这就解决了一切!
标签: java type-conversion rounding file-conversion