Drupal 6 用户密码导入 Drupal 7

Question

除了用户之外，我真的不需要将任何数据导入到我的 D7 构建中。我已经（通过 SQL）导入了我的用户数据，但是 D7 密码加密方法现在不同了。

无论如何我都不是专家，而且我从未使用过 Drush，但我遇到了这个 user_update_7000 代码 sn-p found user.install (http://api.drupal.org/api/drupal/modules--user--user.install/function/user_update_7000/7)

<?php
require_once DRUPAL_ROOT . '/' . variable_get('password_inc', 'includes/password.inc');
$old_hash = md5('password');
$hash_count_log2 = 11;

$new_hash = user_hash_password($old_hash, $hash_count_log2);

if ($new_hash) {
  // Indicate an updated password.
  $new_hash  = 'U' . $new_hash;
}
?>

我可以在哪里运行此脚本来更新数据库中的密码字段？

谢谢，

史蒂夫

Answer 1

我没有足够的积分来添加评论，但我对 hross 的回答做了一些改进（并提交了更新草案）。

这是一个改进的脚本，其中包含文档，并且能够为手动合并 Drupal 6 到 7 的用户指定非默认用户表。它还包含 jpb 的检查。

<?php
  /**
   * Use this script to update Drupal 6 users password hashes to Drupal 7 specs.
   * 
   * Ensure you BACKUP YOUR USERS TABLE before using this script! If not your whole site! 
   * Name this file update_users.php and place in your Drupal root, same place as update.php
   *
   * - If you've manually inserted a new table into your database, change the $databasename below.
   * - If this does not run, ensure you are logged into your site as admin.
   * - If this does not run, check your drupal watchdog and/or PHP logs
   * - If you see this error "PDOException: SQLSTATE[22001]: String data, right truncated: 1406 Data too long for column 'pass' at row 1:"
   *   you need to update your table's structure so that pass is a varchar(128).
   *
   * BACKUP, THIS MAY BREAK YOUR SITE AND EAT YOUR DATA!
   */

  echo "Starting. \r\n";

  // Change this if you've made a custom table
  $databasename = "users";

  // Update this many users
  $count = 1000;

  // bootstrap stuff
  define('DRUPAL_ROOT', getcwd());

  include_once DRUPAL_ROOT . '/includes/bootstrap.inc';
  drupal_bootstrap(DRUPAL_BOOTSTRAP_FULL);

  require_once DRUPAL_ROOT . '/' . variable_get('password_inc', 'includes/password.inc');

  // Lower than DRUPAL_HASH_COUNT to make the update run at a reasonable speed.
  $hash_count_log2 = 11;

  //  Hash again all current hashed passwords.
  $has_rows = FALSE;

  $result = db_query_range("SELECT uid, pass FROM {" . $databasename . "} WHERE uid > 10 ORDER BY uid", 0, $count);
  foreach ($result as $account) {
    $has_rows = TRUE;
    if (substr($account->pass, 0, 1) != 'U') {
      echo "updating account: " . $account->uid . " \r\n";
      $new_hash = user_hash_password($account->pass, $hash_count_log2);
      if ($new_hash) {
        // Indicate an updated password.
        $new_hash  = 'U' . $new_hash;
        db_update($databasename)
          ->fields(array('pass' => $new_hash))
          ->condition('uid', $account->uid)
          ->execute();
      }
    }
  }
  echo "Done.";
?>

Answer 2

这个答案很完美。我用它从 Drupal 5 站点更新。我做了一些更改以适应我的目的：

1. 我没有限制更新的密码数量。我希望所有这些都更新，而我正在更新的系统有超过 1,000 名用户。

2. 我添加了一项检查以确保我没有两次更新密码。这样，如果修改所有密码超时（就像对我一样），我可以重新运行 rehash.php 以完成转换。但是请注意，一旦用户登录，当密码被重新散列时，前导的“U”将被删除。

   if (substr($account->pass, 0, 1) == 'U')
   {
       continue;
   }
   

Answer 3

我认为您可以创建一个名为 rehash.php 的页面（在您的根目录中，与 update.php 相同的位置）。然后，首先以管理员身份登录，然后浏览到此页面。请参阅下面的代码（大部分取自最新的 drupal 7 安装中的 user_update_7200）...

更糟糕的情况是，您可以创建一个简单的自定义模块并将此代码放入其中。

请注意，您应该先备份内容：

<?php
    // bootstrap stuff
    define('DRUPAL_ROOT', getcwd());

    include_once DRUPAL_ROOT . '/includes/bootstrap.inc';
    drupal_bootstrap(DRUPAL_BOOTSTRAP_FULL);

    require_once DRUPAL_ROOT . '/' . variable_get('password_inc', 'includes/password.inc');

    // Lower than DRUPAL_HASH_COUNT to make the update run at a reasonable speed.
    $hash_count_log2 = 11;

    //  Hash again all current hashed passwords.
    $has_rows = FALSE;

    // Update this many users
    $count = 1000;

    $result = db_query_range("SELECT uid, pass FROM {users} WHERE uid > 1 ORDER BY uid", 0, $count);
    foreach ($result as $account) {
      $has_rows = TRUE;
      $new_hash = user_hash_password($account->pass, $hash_count_log2);
      if ($new_hash) {
        // Indicate an updated password.
        $new_hash  = 'U' . $new_hash;
        db_update('users')
          ->fields(array('pass' => $new_hash))
          ->condition('uid', $account->uid)
          ->execute();
      }
    }
?>