如果没有featuredImage博主，如何包含图片网址？

Question

<b:with value='data:post.featuredImage.isYoutube ? resizeImage(data:post.featuredImage.youtubeMaxResDefaultUrl, 945, &quot;945:600&quot;): &quot;https://1.bp.blogspot.com/-aR5w9KXuWGU/XhSDNRAVuhI/AAAAAAAAHG8/dLxcaZxSgh0v85JG0mWRMQyEwqMgpL1_gCLcBGAsYHQ/w420-h280-c/no-image.jpg&quot;' var='highRes'>
  <b:with value='data:post.featuredImage ? data:highRes : &quot;https://1.bp.blogspot.com/-aR5w9KXuWGU/XhSDNRAVuhI/AAAAAAAAHG8/dLxcaZxSgh0v85JG0mWRMQyEwqMgpL1_gCLcBGAsYHQ/w420-h280-c/no-image.jpg&quot;' var='isSource'>
  <a expr:href='data:post.url'>
  <b:include data='{image: data:post.featuredImage,
    imageSizes: [512, 640],
    imageRatio: &quot;640:360&quot;,
    sourceSizes: &quot;(min-width: 954px) 842px,
    (min-width: 801px) calc(640vw - 640px), 
    calc(512vw - 512px)&quot;,
    enhancedSourceset: data:isSource}' name='responsiveImage' />
  </a>
  </b:with>
</b:with>

这是我的代码，效果很好，但是当图像丢失时，url 仍然是空的。

Answer 1

您可以使用data:post.featuredImage ? data:post.featuredImage : ".../no-image.jpg"。

<b:with value='data:post.featuredImage ? data:post.featuredImage : "https://1.bp.blogspot.com/-aR5w9KXuWGU/XhSDNRAVuhI/AAAAAAAAHG8/dLxcaZxSgh0v85JG0mWRMQyEwqMgpL1_gCLcBGAsYHQ/w420-h280-c/no-image.jpg"' var='postImage'>
<b:with value='data:postImage.isYoutube ? resizeImage(data:postImage.youtubeMaxResDefaultUrl, 945, "945:600") : data:postImage' var='highRes'>
  <a expr:href='data:post.url'>
  <b:include data='{image: data:postImage,
    imageSizes: [512, 640],
    imageRatio: "640:360",
    sourceSizes: "(min-width: 954px) 842px,
    (min-width: 801px) calc(640vw - 640px), 
    calc(512vw - 512px)",
    enhancedSourceset: data:highRes,
    imageClass: "class names here"}' name='responsiveImage' />
  </a>
  </b:with>
</b:with>