【发布时间】:2015-10-18 07:41:53
【问题描述】:
我正在尝试更改 ctrlq 的代码(可在此处找到:http://ctrlq.org/code/19747-google-forms-upload-files)以上传多个文件而不是 1 个。
这是我目前所拥有的: HTML:
<form id="myForm">
<input type="text" name="myName" placeholder="Name">
<input type="password" name="psw" placeholder="Password">
<input type="text" name="myFolder" placeholder="Folder Name">
<input type="file" name="myFile" id="filesID" multiple>
<input type="submit" value="Upload File"
onclick="this.value='Uploading..';
google.script.run.withSuccessHandler(fileUploaded)
.uploadFiles(this.parentNode);
return false;">
</form>
<div id="output"></div>
<script>
function fileUploaded(status) {
document.getElementById('myForm').style.display = 'none';
document.getElementById('output').innerHTML = status;
}
</script>
<style>
input { display:block; margin: 20px; }
</style>
谷歌脚本:
function doGet(e) {
return HtmlService.createHtmlOutputFromFile('form.html');
}
function uploadFiles(form) {
try {
var input = document.getElementById('filesID');
var dropbox = "User Files";
var folder, folders = DriveApp.getFoldersByName(dropbox);
if (folders.hasNext()) {
folder = folders.next();
} else {
folder = DriveApp.createFolder(dropbox);
}
for (var i = 0; i < input.length; i++) {
var file = folder.createFile(input.input[i]);
file.setDescription("Uploaded by " + form.myName);
}
return "File uploaded successfully " + file.getUrl();
} catch (error) {
return error.toString();
}
}
我收到错误消息,指出函数 createFile 无法运行。我希望这是因为变量 myFile 最初不是一个数组。如何将所有上传的文件放入一个数组中,然后为每个文件运行 createFile?
谢谢
【问题讨论】:
-
这是我如何处理多个文件上传:stackoverflow.com/questions/28147486/…
标签: html file-upload google-apps-script upload