【问题标题】：Count consecutive blank cells between non-blank cells in a column计算列中非空白单元格之间的连续空白单元格
【发布时间】：2020-02-03 20:37:10
【问题描述】：

我正在尝试计算列中两个非空白单元格之间的空白单元格的数量。特别是这两个日期之间的两个日期和日期。

我已经尝试过COUNTBLANK 以及我在此处和其他类似网站上找到的各种其他公式，但我要么修改错误，要么根本不是我想要的。

My sample worksheet

【问题讨论】：

标签： google-sheets count google-sheets-formula array-formulas gs-vlookup

【解决方案1】：

连续重置计数如下：

=ARRAYFORMULA(IF(
 INDIRECT("G2:G"&COUNTA(F2:F)+1)="", MMULT(N(ROW(
 INDIRECT("G2:G"&COUNTA(F2:F)+1))>=TRANSPOSE(ROW(
 INDIRECT("G2:G"&COUNTA(F2:F)+1)))), N(
 INDIRECT("G2:G"&COUNTA(F2:F)+1)=""))-HLOOKUP(0, MMULT(N(ROW(
 INDIRECT("G2:G"&COUNTA(F2:F)+1))>TRANSPOSE(ROW(
 INDIRECT("G2:G"&COUNTA(F2:F)+1)))), N(
 INDIRECT("G2:G"&COUNTA(F2:F)+1)="")), MATCH(VLOOKUP(ROW(
 INDIRECT("G2:G"&COUNTA(F2:F)+1)), IF(N(
 INDIRECT("G2:G"&COUNTA(F2:F)+1)<>G1:G), ROW(
 INDIRECT("G2:G"&COUNTA(F2:F)+1)), ), 1, 1), VLOOKUP(ROW(
 INDIRECT("G2:G"&COUNTA(F2:F)+1)), IF(N(
 INDIRECT("G2:G"&COUNTA(F2:F)+1)<>G1:G), ROW(
 INDIRECT("G2:G"&COUNTA(F2:F)+1)), ), 1, 1), 0), 0), ))

更新：

=ARRAYFORMULA(QUERY(IF(iF(
 INDIRECT("G2:G"&COUNTA(F2:F)+1)="", MMULT(N(ROW(
 INDIRECT("G2:G"&COUNTA(F2:F)+1))>=TRANSPOSE(ROW(
 INDIRECT("G2:G"&COUNTA(F2:F)+1)))), N(
 INDIRECT("G2:G"&COUNTA(F2:F)+1)=""))-HLOOKUP(0, MMULT(N(ROW(
 INDIRECT("G2:G"&COUNTA(F2:F)+1))>TRANSPOSE(ROW(
 INDIRECT("G2:G"&COUNTA(F2:F)+1)))), N(
 INDIRECT("G2:G"&COUNTA(F2:F)+1)="")), MATCH(VLOOKUP(ROW(
 INDIRECT("G2:G"&COUNTA(F2:F)+1)), IF(N(
 INDIRECT("G2:G"&COUNTA(F2:F)+1)<>G1:G), ROW(
 INDIRECT("G2:G"&COUNTA(F2:F)+1)), ), 1, 1), VLOOKUP(ROW(
 INDIRECT("G2:G"&COUNTA(F2:F)+1)), IF(N(
 INDIRECT("G2:G"&COUNTA(F2:F)+1)<>G1:G), ROW(
 INDIRECT("G2:G"&COUNTA(F2:F)+1)), ), 1, 1), 0), 0), )=1, ARRAY_CONSTRAIN(SORT({IF(INDEX(SORT({
 INDIRECT("G2:G"&COUNTA(F2:F)+1), ROW(
 INDIRECT("G2:G"&COUNTA(F2:F)+1))}, 2, 0),, 1)="", MMULT(N(ROW(
 INDIRECT("G2:G"&COUNTA(F2:F)+1))>=TRANSPOSE(ROW(
 INDIRECT("G2:G"&COUNTA(F2:F)+1)))), N(INDEX(SORT({
 INDIRECT("G2:G"&COUNTA(F2:F)+1), ROW(
 INDIRECT("G2:G"&COUNTA(F2:F)+1))}, 2, 0),, 1)=""))-HLOOKUP(0, MMULT(N(ROW(
 INDIRECT("G2:G"&COUNTA(F2:F)+1))>TRANSPOSE(ROW(
 INDIRECT("G2:G"&COUNTA(F2:F)+1)))), N(INDEX(SORT({
 INDIRECT("G2:G"&COUNTA(F2:F)+1), ROW(
 INDIRECT("G2:G"&COUNTA(F2:F)+1))}, 2, 0),, 1)="")), MATCH(VLOOKUP(ROW(
 INDIRECT("G2:G"&COUNTA(F2:F)+1)), IF(N(INDEX(SORT({
 INDIRECT("G2:G"&COUNTA(F2:F)+1), ROW(
 INDIRECT("G2:G"&COUNTA(F2:F)+1))}, 2, 0),, 1)<>{"×"; INDEX(SORT({
 INDIRECT("G2:G"&COUNTA(F2:F)+1), ROW(
 INDIRECT("G2:G"&COUNTA(F2:F)+1))}, 2, 0),, 1)}), ROW(
 INDIRECT("G2:G"&COUNTA(F2:F)+1)), ), 1, 1), VLOOKUP(ROW(
 INDIRECT("G2:G"&COUNTA(F2:F)+1)), IF(N(INDEX(SORT({
 INDIRECT("G2:G"&COUNTA(F2:F)+1), ROW(
 INDIRECT("G2:G"&COUNTA(F2:F)+1))}, 2, 0),, 1)<>{"×"; INDEX(SORT({
 INDIRECT("G2:G"&COUNTA(F2:F)+1), ROW(
 INDIRECT("G2:G"&COUNTA(F2:F)+1))}, 2, 0),, 1)}), ROW(
 INDIRECT("G2:G"&COUNTA(F2:F)+1)), ), 1, 1), 0), 0), ), ROW(
 INDIRECT("G2:G"&COUNTA(F2:F)+1))}, 2, 0), 999^99, 1), ), "offset 1", 0))

【讨论】：

非常感谢您的回答！是否可以将其反转，使其倒计时而不是倒计时？所以 H9 会是 3？
很可能没有。但是，如果您对可拖动的解决方案感兴趣，它可以完成并且看起来完全像您想要的那样。
@Trey 没关系，一切皆有可能。答案已更新

【解决方案2】：

除了player0提供的解决方案外，我创建了一个额外的表并输入到单元格I2中

=ArrayFormula(if(len(G2:G), iferror(vlookup(G2:G, query({if(row(G2:G) <= max(if(not(isblank(F2:F)), row(G2:G))),vlookup(row(G2:G),filter({row(G2:G),G2:G},len(G2:G)),2),), --isblank(G2:G)}, "Select Col1, Sum(Col2) where Col2 > 0 group by Col1"), 2, 0)),))

看看有没有用？

【讨论】：