猜谜游戏范围

Question

我完成了我的课堂作业，除了一件事还想不通。 如何使程序只允许 1 到 100 范围内的数字？如果用户输入一个小于 1 或大于 100 的数字，它应该告诉用户该数字超出范围。

我设置了一个随机类和一个 while 循环，它接受输入并告诉用户数字太高或太低。如果数字正确，则显示您赢得按摩。一切正常，但只有范围部分。 导入 java.util.Scanner； 导入 java.util.Random;

公共类 GuessingGame {

/**
 * @param args the command line arguments
 */
public static void main(String[] args) {
    // TODO code application logic here

    Random generator = new Random(); 
    int numberToGuess = 1 + generator.nextInt(100);
    int numberOfTries = 0;

    Scanner input = new Scanner (System.in);
    int guess;
    boolean win = false;


    System.out.println("You have 10 tries to guess a number between 1 and 100");

    while(!win && numberOfTries < 10)
    {
    System.out.println("Guess a number: ");
    guess = input.nextInt();

    if (guess < 1 || guess > 100)
    {
    System.out.println("Guess is out of range!");
    continue; 
    }


    if (guess == numberToGuess) 
    {
        win=true;
    }

    else if (guess < numberToGuess)
            {
            System.out.println("Your guess is too low");
            }
    else if (guess > numberToGuess)
            {
            System.out.println("Your guess is too high");
            }

    }

    System.out.println("You win!");
    System.out.println("The number was " + numberToGuess);
    System.out.println("It took you " + numberOfTries + " tries." );


}

} - 我添加了其余的代码 -

但是如果我输入像 -1 或 101 这样的数字，程序会说数字太高或数字太低，忽略超出范围的语句。想不通为什么。 请你帮助我好吗？ 谢谢

Answer 1

好吧，break 将使程序退出while 循环，而没有任何机会再次输入数字。请改用continue。

Answer 2

break关键字用于退出最近的循环体，因为那是你的while循环，使用它会结束你的猜数字游戏。您想使用continue 关键字，它将立即开始循环的下一次迭代：

while(!win && numberOfGuesses < 10)
{
    System.out.println("Guess a number: ");
    guess = Integer.parseInt(input.nextLine());

    if (guess < 1 || guess > 100)
    {
        System.out.println("Guess is out of range!");
        continue; //Use this instead of break
    }

    //Rest of your code
}

Answer 3

我对您的代码进行了一些改进：

numberOfTries++检查有效范围后，因为你需要增加这个数字，否则10次猜测后循环不会结束。

break 当玩家获胜时，因为在这种情况下您不希望循环继续。

在循环之后，您需要检查玩家是否获胜。也有可能他猜了10次没有中奖。

我认为现在它应该可以按预期工作了。

public static void main(String[] args) {
    Random generator = new Random(); 
    int numberToGuess = 1 + generator.nextInt(100);
    int numberOfTries = 0;

    Scanner input = new Scanner (System.in);
    int guess;
    boolean win = false;

    System.out.println("You have 10 tries to guess a number between 1 and 100");

    while(!win && numberOfTries < 10)
    {
        System.out.println("Guess a number: ");
        guess = input.nextInt();

        if (guess < 1 || guess > 100)
        {
            System.out.println("Guess is out of range!");
            continue; 
        }

        // increase numberOfTries by 1 because player made another valid guess
        numberOfTries++;

        if (guess == numberToGuess) 
        {
            win=true;
            // exit the while loop because player won
            break;
        }

        if (guess < numberToGuess)
        {
            System.out.println("Your guess is too low");
        }
        else 
        {
            // guess must be > numberToGuess here
            System.out.println("Your guess is too high");
        }
    }

    if(win)
    {
        System.out.println("You win!");
        System.out.println("The number was " + numberToGuess);
        System.out.println("It took you " + numberOfTries + " tries." );
    }
    else
    {
        System.out.println("Sorry, you didn't win.");
        System.out.println("The right number was " + numberToGuess);
    }
}