【发布时间】:2020-02-11 13:16:09
【问题描述】:
我正在做一个关于在 Linux 平台上创建自主驱动程序的项目。我需要在特定时间捕捉键盘上按下的键,尤其是同时按下它们时。我写了这段代码,它在 Windows 中非常好用,但在 linux 中却不太好:
import time
import cv2
import mss
import numpy as np
from pynput.keyboard import Key, Listener
def up():
print("Go up")
def down():
print("Go down")
def left():
print("Go left")
def right():
print("Go right")
def up_left():
print("Go up_left")
def up_right():
print("Go up_right")
def down_left():
print("Go down_left")
def down_right():
print("Go down_right")
def do_nothing():
print("Do Nothing")
# Create a mapping of keys to function (use frozenset as sets are not hashable - so they can't be used as keys)
# The keys combinatons to check
combination_to_function = {
frozenset([Key.up]): up,
frozenset([Key.down, ]): down,
frozenset([Key.left, ]): left,
frozenset([Key.right, ]): right,
frozenset([Key.up, Key.left]): up_left,
frozenset([Key.up, Key.right]): up_right,
frozenset([Key.down, Key.left]): down_left,
frozenset([Key.down, Key.right]): down_right,
}
# Currently pressed keys
current_keys = set()
def on_press(key):
# When a key is pressed, add it to the set we are keeping track of and check if this set is in the dictionary
current_keys.add(key)
if frozenset(current_keys) in combination_to_function:
# If the current set of keys are in the mapping, execute the function
combination_to_function[frozenset(current_keys)]()
def on_release(key):
# When a key is released, remove it from the set of keys we are keeping track of
if key in current_keys:
current_keys.remove(key)
def process_img(original_img):
processed_img = cv2.cvtColor(original_img, cv2.COLOR_BGR2GRAY)
processed_img = cv2.Canny(processed_img, threshold1=200, threshold2=300)
return processed_img
with mss.mss() as sct:
# Part of the screen to capture
monitor = {"top": 0, "left": 70, "width": 640, "height": 480}
while True:
listener = Listener(on_press=on_press, on_release=on_release)
listener.start()
last_time = time.time()
# key_catcher = MockButton()
# Get raw pixels from the screen, save it to a Numpy array
screen = np.array(sct.grab(monitor))
new_screen = process_img(original_img=screen)
# Display the picture
cv2.imshow("Window", new_screen)
# print("Loop took {} seconds".format(time.time() - last_time))
# Press "q" to quit
k = cv2.waitKey(10)
if k & 0xFF == ord("q"):
cv2.destroyAllWindows()
break
listener.stop()
go_up, go_down, ... 函数只是象征性的,我想编写其他代码来将按下的键转换为机器学习过程的向量。
例如,如果我在键盘上按w,我希望得到这样的向量:
w s a d wa wd sa sd nk
[1 0 0 0 0 0 0 0 0 ]
当我同时按下w 和a 时,我希望这样:
w s a d wa wd sa sd nk
[0 0 0 0 1 0 0 0 0 ]
无论如何,代码在 linux 中运行得不够好。该程序在运行一段时间时遇到了一些问题。程序运行一段时间后,终端停止输出。有人可以帮我让这段代码在 linux 中更高效吗?
【问题讨论】:
-
如果有
cv2.waitKey(),为什么还要使用key_check? -
顺便说一句:
keyList = ["\b"] + list("ABCDEFGHIJKLMNOPQRSTUVWXYZ 123456789,.'£$/\\")但您不必将字符串转换为列表即可在for key on keyList中使用它。它应该可以工作for key in "\bABCDEFGHIJKLMNOPQRSTUVWXYZ 123456789,.'£$/\\": -
顺便说一句:你不必使用
with ... as listener: listener.join()。您可以在循环之前运行listener.start(),在循环之后运行listener.stop()。 -
是否可以检测与
cv2.waitKey()同时按下的键?例如,按下w我希望某个函数运行,而w和A我希望另一个函数运行。所以抓住正确的钥匙很重要。 -
与
cv2.waitKey()按下w后,您将不得不等待几毫秒(几个循环),如果您在下一个循环中获得A,则运行第二个函数。如果你没有得到A,那么你运行第一个函数。但是您无法检查是否同时没有释放w。使用listener,您可能必须这样做 - 您必须等待几个循环才能检查您是否没有按A,但您可以轻松检查您是否没有释放w。
标签: python linux opencv keypress pynput