【发布时间】：2018-05-15 05:15:11
【问题描述】：
我正在尝试在我的 Xcode 项目中编译 SoundTouch 框架， 但老实说，我不知道自己在做什么。
有人有什么指示吗？
到目前为止我做了什么
运行 ./bootstrap 给我以下输出
autoreconf: Entering directory `.'
autoreconf: configure.ac: not using Gettext
autoreconf: running: aclocal -I config/m4 --output=aclocal.m4t
Can't exec "aclocal": No such file or directory at /usr/local/Cellar/autoconf/2.69/share/autoconf/Autom4te/FileUtils.pm line 326.
autoreconf: failed to run aclocal: No such file or directory
如果我没记错的话，Mac OS 没有autoreconf，对吧？
SoundTouch 显然至少需要GCC 4.4，但 Mac OS 只有GCC 4.3，所以我从homebrew 下载了GCC 7，但仅与命令gcc-7 ./bootstrap 一起使用会得到以下输出
gcc-7 bootstrap
ld: warning: ignoring file bootstrap, file was built for unsupported file format ( 0x23 0x20 0x24 0x49 0x64 0x3A 0x20 0x62 0x6F 0x6F 0x74 0x73 0x74 0x72 0x61 0x70 ) which is not the architecture being linked (x86_64): bootstrap
Undefined symbols for architecture x86_64:
"_main", referenced from:
implicit entry/start for main executable
ld: symbol(s) not found for architecture x86_64
collect2: error: ld returned 1 exit status
如何成功编译 SoundTouch？
编辑：
我尝试将基本文件复制到一个文件夹，将其添加到我的项目并编译。
现在我得到这个错误：
Undefined symbols for architecture x86_64:
"soundtouch::SoundTouch::SoundTouch()", referenced from:
MyAudioProcessor::MyAudioProcessor() in libMy.a(PluginProcessor.o)
ld: symbol(s) not found for architecture x86_64
clang: error: linker command failed with exit code 1 (use -v to see invocation)
为什么说有未定义的符号？
【问题讨论】：
标签： c++ xcode macos gcc soundtouch