【发布时间】:2021-07-10 16:54:42
【问题描述】:
我的数据库中有两个模型 Parent 和 Child,这两个模型之间存在一对多的关系,即一个父母可以有多个孩子。
from flask import Flask, request
from flask_restful import Resource
from flask_sqlalchemy import SQLAlchemy
from flask_marshmallow import Marshmallow
from flask_restful import Api
from marshmallow import fields
app = Flask(__name__)
app.config["SQLALCHEMY_DATABASE_URI"] = "sqlite:///relationships.db"
db = SQLAlchemy(app)
ma = Marshmallow(app)
api = Api(app, prefix="/api")
class Parent(db.Model):
id = db.Column(db.Integer, primary_key=True)
name = db.Column(db.String(20), nullable=False, unique=True)
children = db.relationship("Child", backref="parent")
class Child(db.Model):
id = db.Column(db.Integer, primary_key=True)
name = db.Column(db.String(20), nullable=False, unique=True)
parent_id = db.Column(db.Integer, db.ForeignKey("parent.id"))
class ChildSchema(ma.SQLAlchemyAutoSchema):
class Meta:
model = Child
ordered = True
include_fk = True
dump_only = ("id",)
load_instance = True
class ParentSchema(ma.SQLAlchemyAutoSchema):
children = fields.Pluck(ChildSchema, "name", many=True)
class Meta:
model = Parent
ordered = True
include_relationships = True
dump_only = ("id",)
load_instance = True
class ParentResource(Resource):
@classmethod
def get(cls, _id: int):
parent_schema = ParentSchema()
return parent_schema.dump(parent.query.filter_by(id=_id).first()), 200
@classmethod
def put(cls, _id: int):
parent_json = request.get_json()
parent_schema = ParentSchema()
parent_input_data = parent_schema.load(parent_json)
parent = Parent.query.filter_by(id=_id).first()
parent.name = parent_input_data.name
child_names = [child.name.lower() for child in parent.children]
# Check if child is not already in parent children list
for child_input in parent_input_data.children:
if child_input.name.lower() not in child_names:
parent.children.append(child_input)
db.session.add(parent)
db.session.commit()
return {"message": "Updated"}, 200
api.add_resource(ParentResource, "/parent/<int:_id>")
if __name__ == "__main__":
db.create_all()
app.logger.info("Starting app...")
app.run("127.0.0.1", 3003)
当我尝试通过添加一些新子项来更新父项时,我收到一个唯一键约束错误,因为似乎 SQLAlchemy 正在尝试在父表中运行插入查询,而不是尝试更新父表记录。父表中已经有一条同名“ABCD”的记录,即我只是尝试保持父名称不变并更新子表。
这是我为 PUT 请求提供的输入。
{
"name": "ABCD",
"children": [
"Tom",
"Spot"
]
}
有人可以帮我理解我哪里出错了吗?当我尝试更新父级而不尝试更新子级时,更新似乎按预期工作。仅当我尝试更新子关系时才会出现此问题。
【问题讨论】:
-
尝试在
ParentResource.put方法中注释掉db.session.add(parent)。我认为您的对象已经在 db.session 中,因为您查询了它。stackoverflow.com/a/48592786/13468 -
我也试过了,得到同样的错误。它再次尝试执行 INSERT。 sqlalchemy.exc.IntegrityError: (sqlite3.IntegrityError) UNIQUE 约束失败:parent.name [SQL: INSERT INTO parent (name) VALUES (?)]
标签: python python-3.x sqlite flask sqlalchemy