【发布时间】:2020-02-13 10:32:15
【问题描述】:
亲爱的,我在使用 JPQL 查询时遇到问题,当我使用 IN 和 List(Long) 时出现错误,但并非总是如此
this is the model (是查看关系的最小模型,没有所有列)
如果我在 mi repo 中进行此查询工作正常:
@Query(value = "SELECT a FROM Artist a WHERE a.idArtist IN(SELECT a.idArtist FROM ArtistStyle x "
+ "INNER JOIN x.style s "
+ "INNER JOIN x.artist a "
+ "WHERE s.idStyle IN (:arrayStyles))")
public List<Artist> FilterArtistWithStyles(List<Long> arrayStyles);
但如果我执行此查询,我会得到错误:
@Query(value = "SELECT a FROM Artist a WHERE a.idArtist IN(SELECT a.idArtist FROM ArtistStyle x "
+ "INNER JOIN x.style s "
+ "INNER JOIN x.artist a "
+ "INNER JOIN a.country c "
+ "INNER JOIN a.aal1 a1 "
+ "INNER JOIN a.aal2 a2 "
+ "INNER JOIN a.aal3 a3 "
+ "WHERE (:arrayStyles IS NULL OR s.idStyle IN (:arrayStyles)) "
+ "AND (:name IS NULL OR a.name like %:name%)" + "AND (:gender IS NULL OR a.gender = :gender) "
+ "AND (:experienceFrom IS NULL OR a.workStartYear <= :experienceFrom) "
+ "AND (:ratingFrom IS NULL OR a.ratingAccordance >= :ratingFrom) "
+ "AND (:delivery IS NULL OR a.delivery = :delivery) "
+ "AND (:exchange IS NULL OR a.exchange = :exchange) " + "AND (:courses IS NULL OR a.courses = :courses)"
+ "AND (:idCountry IS NULL OR c.idCountry = :idCountry)"
+ "AND (:idAal1 IS NULL OR a1.idAdministrativeAreaLevel1 = :idAal1)"
+ "AND (:idAal2 IS NULL OR a2.idAdministrativeAreaLevel2 = :idAal2)"
+ "AND (:idAal3 IS NULL OR a3.idAdministrativeAreaLevel3 = :idAal3)" + ")")
public List<Artist> SearchArtistWithStyles(String name, List<Long> arrayStyles, Integer gender, Integer experienceFrom, Double ratingFrom, Integer delivery,
Integer exchange, Integer courses, Long idCountry, Long idAal1, Long idAal2, Long idAal3,
Pageable pageable);
这是错误:
"status": 500,
"error": "Internal Server Error",
"message": "org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected AST node: {vector} [SELECT a FROM com.mushroomstudios.skink.entities.Artist a WHERE a.idArtist IN(SELECT a.idArtist FROM com.mushroomstudios.skink.entities.ArtistStyle x INNER JOIN x.style s INNER JOIN x.artist a INNER JOIN a.country c INNER JOIN a.aal1 a1 INNER JOIN a.aal2 a2 INNER JOIN a.aal3 a3 WHERE (:arrayStyles_0, :arrayStyles_1, :arrayStyles_2 IS NULL OR s.idStyle IN (:arrayStyles_0, :arrayStyles_1, :arrayStyles_2)) AND (:name IS NULL OR a.name like :name)AND (:gender IS NULL OR a.gender = :gender) AND (:experienceFrom IS NULL OR a.workStartYear <= :experienceFrom) AND (:ratingFrom IS NULL OR a.ratingAccordance >= :ratingFrom) AND (:delivery IS NULL OR a.delivery = :delivery) AND (:exchange IS NULL OR a.exchange = :exchange) AND (:courses IS NULL OR a.courses = :courses)AND (:idCountry IS NULL OR c.idCountry = :idCountry)AND (:idAal1 IS NULL OR a1.idAdministrativeAreaLevel1 = :idAal1)AND (:idAal2 IS NULL OR a2.idAdministrativeAreaLevel2 = :idAal2)AND (:idAal3 IS NULL OR a3.idAdministrativeAreaLevel3 = :idAal3)) order by a.name asc]; nested exception is java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected AST node: {vector} [SELECT a FROM com.mushroomstudios.skink.entities.Artist a WHERE a.idArtist IN(SELECT a.idArtist FROM com.mushroomstudios.skink.entities.ArtistStyle x INNER JOIN x.style s INNER JOIN x.artist a INNER JOIN a.country c INNER JOIN a.aal1 a1 INNER JOIN a.aal2 a2 INNER JOIN a.aal3 a3 WHERE (:arrayStyles_0, :arrayStyles_1, :arrayStyles_2 IS NULL OR s.idStyle IN (:arrayStyles_0, :arrayStyles_1, :arrayStyles_2)) AND (:name IS NULL OR a.name like :name)AND (:gender IS NULL OR a.gender = :gender) AND (:experienceFrom IS NULL OR a.workStartYear <= :experienceFrom) AND (:ratingFrom IS NULL OR a.ratingAccordance >= :ratingFrom) AND (:delivery IS NULL OR a.delivery = :delivery) AND (:exchange IS NULL OR a.exchange = :exchange) AND (:courses IS NULL OR a.courses = :courses)AND (:idCountry IS NULL OR c.idCountry = :idCountry)AND (:idAal1 IS NULL OR a1.idAdministrativeAreaLevel1 = :idAal1)AND (:idAal2 IS NULL OR a2.idAdministrativeAreaLevel2 = :idAal2)AND (:idAal3 IS NULL OR a3.idAdministrativeAreaLevel3 = :idAal3)) order by a.name asc]",
最后,如果我做那个查询,也可以正常工作:
@Query(value = "SELECT a FROM Artist a " + "INNER JOIN a.country c "
+ "INNER JOIN a.aal1 a1 "
+ "INNER JOIN a.aal2 a2 "
+ "INNER JOIN a.aal3 a3 "
+ "WHERE (:name IS NULL OR a.name like %:name%) "
+ "AND (:gender IS NULL OR a.gender = :gender) "
+ "AND (:experienceFrom IS NULL OR a.workStartYear <= :experienceFrom) "
+ "AND (:ratingFrom IS NULL OR a.ratingAccordance >= :ratingFrom) "
+ "AND (:delivery IS NULL OR a.delivery = :delivery) "
+ "AND (:exchange IS NULL OR a.exchange = :exchange) " + "AND (:courses IS NULL OR a.courses = :courses)"
+ "AND (:idCountry IS NULL OR c.idCountry = :idCountry)"
+ "AND (:idAal1 IS NULL OR a1.idAdministrativeAreaLevel1 = :idAal1)"
+ "AND (:idAal2 IS NULL OR a2.idAdministrativeAreaLevel2 = :idAal2)"
+ "AND (:idAal3 IS NULL OR a3.idAdministrativeAreaLevel3 = :idAal3)")
public List<Artist> SearchArtist(String name, Integer gender, Integer experienceFrom, Double ratingFrom,
Integer delivery, Integer exchange, Integer courses, Long idCountry, Long idAal1, Long idAal2, Long idAal3,
Pageable pageable);
第二个查询有什么不好的地方吗?如果您需要更多信息,例如实体或其他信息,请告诉我,提前谢谢
【问题讨论】:
-
Idk 如果这是原因,但您正在重用
a别名 -
Offtopic:
a.name like %:name%是性能杀手。 -
谢谢,但我认为如果我使用 (:name IS NULL OR a.name like %:name%) 只有在 :name 值不为空时才会执行类似的操作,如果用户不要输入任何内容。无论如何,那样是性能杀手吗?我可以用其他方式代替吗?
-
它的名字是空的,而不是这个子句,但如果不是 - 你将有非索引的整个表匹配搜索。