【发布时间】:2017-02-18 19:58:38
【问题描述】:
我是 Mongo Aggregation 的新手并拥有这些数据
{
"_id": {
"$oid": "5654a8f0d487dd1434571a6e"
},
"ValidationDate": {
"$date": "2015-11-24T13:06:19.363Z"
},
"DataRaw": " WL 00100100012015-08-28 02:44:17+0000+ 16.81 8.879 1084.00",
"ReadingsAreValid": true,
"locationID": " WL 001",
"Readings": {
"pH": {
"value": 8.879
},
"SensoreDate": {
"value": {
"$date": "2015-08-28T02:44:17.000Z"
}
},
"temperature": {
"value": 16.81
},
"Conductivity": {
"value": 1084
}
},
"HMAC":"ecb98d73fcb34ce2c5bbcc9c1265c8ca939f639d791a1de0f6275e2d0d71a801"
}
我的目标是计算每两小时间隔的平均温度,然后计算每月、每年和每周的平均温度。我尝试了各种查询,但没有运气。这是我迄今为止尝试过的
data.aggregate([{"$unwind":"$Readings"},
{"$project":{"HourRecord":{"$hour":"Readings.SensoreDate.value"},
"YearRecord":{"$year":"$Readings.SensoreDate.value"}}},
{'$group' : {'_id' : "$locationID",
'AverageTemp' : { '$avg' : '$Readings.temperature.value'}}}
])
我得到一个像这样的空结果
{u'ok': 1.0, u'waitedMS': 0L, u'result': [{u'AverageTemp': None, u'_id': None}]}
我尝试了其他几种组合,但结果仍然为空。
以下查询每小时、每月等返回所需的结果,但如何按两小时间隔而不是一小时分组
test_Agg.aggregate([{"$unwind":"$Readings"},
{"$project":{ "HourRecord": { "$hour":"$Readings.SensoreDate.value"},
"YearRecord": {"$year":"$Readings.SensoreDate.value"},
"MonthRecord": {"$month":"$Readings.SensoreDate.value"},
"locationID" : 1,
"Readings.pH.value":1,
'Readings.temperature.value' : 1}
},
{'$group' : {'_id' :"$HourRecord",
'AverageTemp' : { '$avg' : '$Readings.temperature.value'}}
}])
【问题讨论】:
标签: mongodb python-2.7 pymongo aggregation-framework mongodb-aggregation