从键中提取 JSON 值

Question

我有一个这样的 JSON 对象，我需要使用 id 提取任何对象的 name 值。我已经尝试了许多不同的迭代，但我似乎无法得到任何工作。任何一般的指针将不胜感激。谢谢。

{
  "weeks":[
    {
      "1":[
        {
          "name":"Stackoverflow Question",
          "description":"Have you ever asked a question on StackoverFlow?",
          "date":"11/25/2019",
          "id":"whewhewhkahfasdjkhgjks"
        },
        {
          "name":"I Can't Believe It's Not Butter!",
          "description":"Can you believe it? I sure can't.",
          "date":"11/25/2019",
          "id":"agfasdgasdgasdgawe"
        }
      ]
    },
    {
      "2":[
        {
          "name":"Hello World",
          "description":"A hello world.",
          "date":"12/02/2019",
          "id":"aewgasdgewa"
        },
        {
          "name":"Testing 123",
          "description":"Sometimes people don't say it be like it is but it do.",
          "date":"12/04/2019",
          "id":"asdgasdgasdgasd"
        }
      ]
    }
  ]
}

Answer 1

结构是固定的，还是 JSON 的深度可以与示例不同？

如果有更多或更少的层次结构，这个也可以工作。 它基本上在类 JSON 结构内的每个字典中搜索 field_name 并返回参数 output_name 的值。

也许当你的数据结构发生变化时它会帮助你:)

data = {
  "weeks":[
    {
      "1":[
        {
          "name":"Stackoverflow Question",
          "description":"Have you ever asked a question on StackoverFlow?",
          "date":"11/25/2019",
          "id":"whewhewhkahfasdjkhgjks"
        },
        {
          "name":"I Can't Believe It's Not Butter!",
          "description":"Can you believe it? I sure can't.",
          "date":"11/25/2019",
          "id":"agfasdgasdgasdgawe"
        }
      ]
    },
    {
      "2":[
        {
          "name":"Hello World",
          "description":"A hello world.",
          "date":"12/02/2019",
          "id":"aewgasdgewa"
        },
        {
          "name":"Testing 123",
          "description":"Sometimes people don't say it be like it is but it do.",
          "date":"12/04/2019",
          "id":"asdgasdgasdgasd"
        }
      ]
    }
  ]
}

def extract_name(data, field_name: str, matching_value: str, output_name: str):
    """

    :param data: json-like datastructure in which you want to search
    :param field_name: the field name with which you want to match
    :param matching_value: the value you want to match
    :param output_name: the name of the value which you want to get
    :return:
    """
    if isinstance(data, list):
        for item in data:
            res = _inner_extract_name(item, field_name, matching_value, output_name)
            if res is not None:
                return res
    elif isinstance(data, dict):
        for item in data.values():
            res = _inner_extract_name(item, field_name, matching_value, output_name)
            if res is not None:
                return res


def _inner_extract_name(item, field_name, matching_value, output_name):
    if isinstance(item, dict):
        res = extract_name(item, field_name, matching_value, output_name)
        if field_name in item:
            if item[field_name] == matching_value:
                if output_name in item:
                    return item[output_name]
    else:
        res = extract_name(item, field_name, matching_value, output_name)
    return res


if __name__ == "__main__":
    name = extract_name(data, "id", "aewgasdgewa", "name")
    print(name)
``

Answer 2

希望你需要根据id找到名字，然后试试下面的代码，

def get_name(data, id):
    for week in data['weeks']:
        for i in week:
            for j in week[i]:
                if j['id'] == id:
                    return j['name']
    return None

get_name(data, 'asdgasdgasdgasd')

输出

'Testing 123'

Answer 3

不确定这是不是你要找的东西

for week in a["weeks"]:
    for k, v in week.values():
        print(v['name'])

考虑到你的字典变量。