【发布时间】:2014-08-03 10:58:08
【问题描述】:
我一直在为数组问题苦苦挣扎。例如,如果我有以下 3 维数组:
import os
import numpy as np
myArray = [[[1,2,3],
[0,0,0],
[2,2,2]],
[[0,1,2],
[1,1,1],
[3,3,3]],
[[2,3,4],
[5,6,7],
[8,9,10]]]
我想以递归方式为 myArray[0] 中的每个位置定义一个列表,该列表将存储 Z 轴上的值,以便:
list1 = [myArray[0][0][0],myArray[1][0][0], myArray[2][0][0]] # would be [1,0,2]
list2 = [myArray[0][0][1],myArray[1][0][1], myArray[2][0][1]] # would be [2,1,3]
list3 = [myArray[0][0][2],myArray[1][0][2], myArray[2][0][2]] # would be [3,2,4]
list4 = [myArray[0][1][0],myArray[1][1][0], myArray[2][1][0]] # would be [0,1,5]
list5 = [myArray[0][1][1],myArray[1][1][1], myArray[2][1][1]] # would be [0,1,6]
list6 = [myArray[0][1][2],myArray[1][1][2], myArray[2][1][2]] # would be [0,1,7]
list7 = [myArray[0][2][0],myArray[1][2][0], myArray[2][2][0]] # would be [2,3,8]
list8 = [myArray[0][2][1],myArray[1][2][1], myArray[2][2][1]] # would be [2,3,9]
list9 = [myArray[0][2][2],myArray[1][2][2], myArray[2][2][2]] # would be [2,3,10]
我猜它必须类似于
for i in range(len(myArray[0])-1):
list+str(i) =[something]
你知道如何生成这个吗?
非常感谢
【问题讨论】:
标签: python arrays list recursion