我想删除数组中的重复值并获得唯一值答案

【问题标题】：I want to remove duplicated values in side an array and get unique value我想删除数组中的重复值并获得唯一值
【发布时间】：2020-11-02 06:45:57
【问题描述】：

例如看这个数组，我想删除那些“年龄”值相同的对象。

var array =[
{age:21,name:"sam",class="C"},
{age:24,name:"david",class="f"},
{age:45,name:"zack",class="f"},
{age:21,name:"jeff",class="g"},
{age:21,name:"marco",class="a"},
{age:26,name:"john",class="d"},
];

我想得到这个结果：

[
{age:21,name:"sam",class="C"},
{age:24,name:"david",class="f"},
{age:45,name:"zack",class="f"},
{age:26,name:"john",class="d"},
];

【问题讨论】：

标签： javascript arrays object distinct-values

【解决方案1】：

您可以使用reduce

var array = [
{age:21,name:"sam",class:"C"},
{age:24,name:"david",class:"f"},
{age:45,name:"zack",class:"f"},
{age:21,name:"jeff",class:"g"},
{age:21,name:"marco",class:"a"},
{age:26,name:"john",class:"d"}
];

let result = array.reduce((a,v) => {
   let i = a.findIndex(person => person.age === v.age);
   if(i !== -1){
      return a;
   }
   return [...a, {...v}];
},[]);

console.log(result);

【讨论】：

【解决方案2】：

你可以这样做

var array =[
{age:21,name:"sam",class:"C"},
{age:24,name:"david",class:"f"},
{age:45,name:"zack",class:"f"},
{age:21,name:"jeff",class:"g"},
{age:21,name:"marco",class:"a"},
{age:26,name:"john",class:"d"},
];

var res = array.filter((i, index, self) => self.findIndex(k => k.age === i.age)==index);
console.log(res);

   //Another clever way with lesser complexity :)
   

  var res = array.reduce((a,v)=>{
    if(!a[v.age]){
      a[v.age] = v
    };
    return a

   },{})

  console.log(Object.values(res))

【讨论】：