您要查找的是 GROUP BY。
如果不查看您的数据,很难提出确切的查询,但我已经创建了一些测试数据。
create table House (HouseId int, HouseName nvarchar(max));
insert into House (HouseId, HouseName) values (1,'House A'), (2, 'House B'), (3,'House C');
create table Room (RoomId int, RoomName nvarchar(max), HouseId int);
insert into Room (RoomId, RoomName, HouseId)
values
(1,'Room 1 in house A', 1), (2,'Room 2 in house A', 1),
(3,'Room 3 in house B', 2),(4,'Room 4 in house B', 2),
(5,'Room 5 in house C', 3),(6,'Room 6 in house C', 3)
create table Resident (ResidentId int, ResidentName nvarchar(max), RoomId int, Result int);
insert into Resident (ResidentId, ResidentName, RoomId, Result)
values
-- House A = 4 passed, 0 failed
(1, 'Resident 1 in Room 1', 1, 82), (2, 'Resident 2 in Room 1', 1, 76),
(3, 'Resident 3 in Room 2', 2, 91), (4, 'Resident 4 in Room 2', 2, 67),
-- House B = 2 passed, 2 failed
(5, 'Resident 5 in Room 3', 3, 60), (6, 'Resident 6 in Room 3', 3, 64),
(7, 'Resident 7 in Room 4', 4, 28), (8, 'Resident 8 in Room 4', 4, 42),
-- House C = 3 passed, 1 failed
(9, 'Resident 9 in Room 5', 5, 99), (10, 'Resident 10 in Room 5', 5, 57),
(9, 'Resident 11 in Room 6', 6, 75), (10, 'Resident 12 in Room 6', 6, 38)
那么您的查询将类似于:
select
HouseName,
[Passed] = SUM(x.Passed),
[Failed] = SUM(x.Failed)
from
Resident re
outer apply (
--// Logic to determine if they passed or failed
--// I arbitrarily chose the number 50 to be the threshold
select [Passed] = case when re.Result >= 50 then 1 else 0 end,
[Failed] = case when re.Result < 50 then 1 else 0 end
) x
inner join Room r on r.RoomId = re.RoomId
inner join House h on h.HouseId = r.HouseId
group by
h.HouseName
这是一个小提琴:http://sqlfiddle.com/#!18/30894/1