通过python将带有'th''st''rd''nd'的日期字符串转换为日期格式

Question

我正在使用漂亮的汤来报废一个网站。这是CSS

<div id="listing-details-list">
<h3 class="listing-details-header">
Details:
<span>Posted on: 14th June 2016</span>
</h3>
</div>

我用来获取日期的代码是这样的

# date
    try:
        date=soup.find("h3","listing-details-header") 
        date_result= str(date.get_text().encode("utf-8").strip()[20:])
        print "\nPublished date: ", date_result
    except StandardError as e:
        date_result="Error was {0}".format(e)
        print date_result

我得到的结果是一个日期作为字符串。一些样本是

23rd June 2016
21st July 2016
20th July 2016
3rd July 2016

现在，我希望日期是一个正确的日期，格式如下所示，以便我可以对其进行计算

23/6/2016
21/7/2016
20/7/2016
3/7/2016

在我的代码中获得所需日期的最佳方法是什么？

我希望以这种方式保存日期：

Month= 6
Day = 23
Year = 2016

---

我尝试了标记为最佳答案的解决方案，它有效

try:
        date=soup.find("h3","listing-details-header") 
        date_result= str(date.get_text().encode("utf-8").strip()[20:])
        date_result=parse(date_result) #added
        month = date_result.month
        day = date_result.day
        year = date_result.year
        print month
        print day
        print year

        print "\nPublished date: ", date_result
    except StandardError as e:
        date_result="Error was {0}".format(e)
        print date_result

Answer 1

要解析日期，我会让dateutil parser 完成这项工作：

>>> from dateutil.parser import parse
>>> l = ["23rd June 2016", "21st July 2016", "20th July 2016", "3rd July 2016"]
>>> for item in l:
...     parse(item)
... 
datetime.datetime(2016, 6, 23, 0, 0)
datetime.datetime(2016, 7, 21, 0, 0)
datetime.datetime(2016, 7, 20, 0, 0)
datetime.datetime(2016, 7, 3, 0, 0)

您将获得 datetime 实例，您可以使用这些实例来执行与日期或时间相关的计算。

我还会改进您在页面上定位所需元素并提取日期的方式：

from dateutil.parser import parse
from bs4 import BeautifulSoup

data = """
<div id="listing-details-list">
<h3 class="listing-details-header">
Details:
<span>Posted on: 14th June 2016</span>
</h3>
</div>"""

soup = BeautifulSoup(data, "html.parser")

for item in soup.find_all("span", text=lambda text: text and text.startswith("Posted on:")):
    date_string = item.get_text().split(": ")[-1]
    print(parse(date_string))