每 3 个字符串后用空格替换逗号

【问题标题】：Replace comma with space after each 3 strings每 3 个字符串后用空格替换逗号
【发布时间】：2016-06-15 13:02:02
【问题描述】：

我有一个 csv 文件，如下所示：

"user1","track1","player1","user1","track2","player2","user1","track3","player3",........

我需要做的是用空格替换逗号（不是所有的逗号），只有那些在 playerIds 之后的逗号（指定一行，以便稍后将它们导入 Mysql）。所以，我需要这样的结果：

"user1","track1","player1" "user1","track2","player2" "user1","track3","player3" ........

我发现我们可以用sed代替逗号和空格：

sed 's/,/ /g' output.csv >output2.csv

但是，它将所有逗号替换为空格。我不知道如何在每 3 个字符串之后执行此操作。任何想法？

谢谢，

【问题讨论】：

【解决方案1】：

你可以像这样使用sed：

sed -E 's/(([^,]*,){2}[^,]*),/\1 /g' file

"user1","track1","player1" "user1","track2","player2" "user1","track3","player3"

【讨论】：

感谢您的回复..但它不起作用:(现在的输出就像"user1","track1","player1”,”user1","track2","player2”,”user1","track3","player3"
我已经在我的回答中包含了输出 sed 命令。这不是你所期待的吗？
是的，但是很奇怪，因为当我写你的命令时，我的输出是不同的......这是我运行你的命令后得到的 uotput："user1","track1","player1”,”user1","track2","player2”,”user1","track3","player3‌" :|
好的，它显示了这个输出："user1","track1","player1" "user1","track2","player2" "user1","track3","player3" .. 但是，它在文件中没有改变，你能告诉我如何在文件中改变它吗？
谢谢！我也可以通过添加以下内容来更改文件：file >file2