【发布时间】:2020-01-30 07:36:05
【问题描述】:
我使用下面的代码将图像发送到 post 方法并将其保存为数据库中的 BLOB 并且它工作成功:
角码:
public postUploadedFile(file:any){
this.formData = new FormData();
this.formData.append('file',file,file.name);
this.Url='http://localhost:38300/api/site/PostUploadFiles';
console.log("url passed from here",this.Url)
return this.http.post(this.Url , this.img).subscribe()
}
API 代码:
public IHttpActionResult PostUploadFiles()
{
int i = 0;
var uploadedFileNames = new List<string>();
string result = string.Empty;
HttpResponseMessage response = new HttpResponseMessage();
var httpRequest = HttpContext.Current.Request;
if (httpRequest.Files.Count > 0)
{
while(i < httpRequest.Files.Count && result != "Failed")
{
br = new BinaryReader(httpRequest.Files[i].InputStream);
ImageData = br.ReadBytes(httpRequest.Files[i].ContentLength);
br.Close();
if (DB_Operation_Obj.Upload_Image(ImageData) > 0)
{
result = "success";
}
else
{
result = "Failed";
}
i++;
}
}
else
{
result = "can't find images";
}
return Json(result);
}
但现在我需要发送更多带有图像的信息(类型 id、名称),而不仅仅是图像,所以角度代码将类似于:
public postUploadedFile(file:any, type_id:number,site_id:number){
this.img = new Image_List();
this.img.images = new Array<PreviewURL>();
this.img.type_id= type_id;
this.img.Reference_id = site_id;
this.img.images.push(file);
this.formData = new FormData();
this.formData.append('file',file,file.name);
this.Url='http://localhost:38300/api/site/PostUploadFiles';
console.log("url passed from here",this.Url)
return this.http.post(this.Url , this.img).subscribe()
}
发送和插入数据库的任何帮助。
【问题讨论】:
标签: c# angular api web-services image-uploading