随机数生成器失败答案

【问题标题】：Random Number generator fail随机数生成器失败
【发布时间】：2016-08-25 21:20:30
【问题描述】：

如果选择了不正确的数字，如何让程序从头开始循环？我不确定我做错了什么。我试过ifs、do whiles、whiles 和if elses：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace ArrayProblms
{
    class Program
    {
        public static void Main(string[] args)
        {
            Console.WriteLine("Guess a number between 1 and 10: ");
            RandomNumberGenerator();
            Console.ReadLine();
        }

        public static void RandomNumberGenerator()
        {
            Random rand = new Random();
            int userValue = int.Parse(Console.ReadLine());
            int randValue = rand.Next(1, 11);
            int attempts = 0;

            if (userValue == randValue)
            {
                Console.WriteLine("You have guessed correctly!");
            }
            while (userValue != randValue)
            {
                Console.WriteLine("You have guessed incorrectly");
                attempts++;
                Console.WriteLine("You have made {0} incorrect guesses", attempts);
                break;
            }
        }
    }
}

【问题讨论】：

程序结束的条件是什么，反复循环的条件是什么？

标签： c# linq visual-studio functional-programming

【解决方案1】：

您应该将int userValue = int.Parse(Console.ReadLine()); 放入循环中，并在每次迭代时检查输入。 break 必须仅当 userValue == randValue:

    public static void RandomNumberGenerator()
    {
        Random rand = new Random();

        int randValue = rand.Next(1, 11);
        int attempts = 0;


        while (true)
        {
            int userValue = int.Parse(Console.ReadLine()); // input inside the loop
            if (userValue == randValue) // checking inside the loop
            {
                Console.WriteLine("You have guessed correctly!");
                break;
            }

            Console.WriteLine("You have guessed incorrectly");
            attempts++;
            Console.WriteLine("You have made {0} incorrect guesses",            attempts);                
        }

    }

【讨论】：

【解决方案2】：

我会使用do...while 继续要求用户输入新号码，直到他猜对为止。

下面的例子：

public static void RandomNumberGenerator()
{
    Random rand = new Random();

    int randValue = rand.Next(1, 11);
    int attempts = 0;

    // do...while cycle to ask user to enter new value each time the used has been wrong
    do
    {
        // read user input
        int userValue = int.Parse(Console.ReadLine());

        // if user guessed correct
        if (userValue == randValue)
        {
            Console.WriteLine("You have guessed correctly!");
            // go away from do...while loop
            // it will stop asking user and will exit from the method
            break;
        }

        // if user has been wrong
        Console.WriteLine("You have guessed incorrectly");
        // increment attempts count
        attempts++;
        Console.WriteLine("You have made {0} incorrect guesses", attempts);
    }
    // and repeat until user guessed correctly
    while(userValue != randValue)
}

【讨论】：

Try this: 没有解释任何内容。我们是否必须逐行比较代码才能看到您修复了什么？
我放了一个 cmets 来描述示例代码的作用。我希望它会有所帮助

【解决方案3】：

您在正确的轨道上，但您需要将 Console.ReadLine 放入 while 循环中，并且仅当用户的值匹配时，break 才会退出循环。

类似这样的伪代码：

Generate random number
while (true) {
    Get value from user
    If it matches, break
}

【讨论】：