while循环只输出一行答案

【问题标题】：while loop is only outputing one rowwhile循环只输出一行
【发布时间】：2018-10-09 20:10:29
【问题描述】：

当我在循环内的每个变量之前使用 echo 时，while 循环内的数据工作正常，但在循环外，php 似乎无法识别变量，即使数据库有不止一行，也只打印一次。请帮忙！

    if($process['organdoner']=="Yes" && $processorgan['bloodtype']== $process['bloodtype'] && $processorgan['bodytype']== $process['bodytype']  ){ //with same bloodtype,bodytype,intensivecare
        $to=$process['email'];
        $header= "Organ is urgently needed";
        $phquery="SELECT personprofile.firstname,personprofile.lastname,personprofile.fathername,hospital.hospitalname,hospital.geolocation 
        FROM personprofile,hospital,areaname 
        WHERE areaname.id= hospital.area AND personprofile.hospitaladmission= hospital.id AND areaname.area='$city' AND personprofile.admissionreason= 5";
        $fetchospitalperson=  mysqli_query($link,$phquery);
        $processtable=mysqli_fetch_assoc($fetchospitalperson);
        do{
         $messagebody= "Patient Name: ".$processtable['firstname']." ".$processtable['fathername']." ".$processtable['lastname']."  "."Hospital Name:"; 

        //$hyperlink= new DOMDocument();
        //$hyperlink->loadHTML("<html><body><a href='<".$processtable['geolocation']."'>" .$processtable['hospitalname']."</a></body></html>"); 
         $hyperlink= "<html><body><a href='<".$processtable['geolocation']."'>".$processtable['hospitalname']."</a></body></html>";
         //Name of the person that needs the blood transfusion along with hospital he is staying at,hyperlinked to its location
        }while($processtable=mysqli_fetch_assoc($fetchospitalperson));

    $message= "Dear"." ".$firstname." ".$lastname.",".PHP_EOL .$messagebody.$hyperlink.PHP_EOL; 
    if(isset($sendtoperson)){   
        if(mail($to,$header,$message)){
            echo "Sent";
        }
        else{ echo "Not sent";}
    }
}

【问题讨论】：

标签： php sql while-loop

【解决方案1】：

您每次循环时都会覆盖变量，因此不要使用x=y，而是使用连接器x .= y

do{
     $messagebody .= "Patient Name: ".$processtable['firstname']." ".$processtable['fathername']." ".$processtable['lastname']."  "."Hospital Name:"; 

     $hyperlink .= "<html><body><a href='<".$processtable['geolocation']."'>".$processtable['hospitalname']."</a></body></html>";

}while($processtable=mysqli_fetch_assoc($fetchospitalperson));

【讨论】：

虽然我不确定只是附加内容会带来任何有意义的东西。