如何关闭一个while循环然后执行另一个代码块？虽然循环总是重复

Question

刚开始学习 Python，如果这个问题看起来很明显，请多多包涵。我正在尝试创建一个高分程序，其中该程序将使用列表方法来创建和维护计算机游戏的用户最佳分数列表。然而，发生的事情是，虽然我根据用户输入编写了代码，但 while 循环继续执行并忽略用户输入。请看下面的代码，希望能回答我做错了什么。提前致谢。

scores =[]
choice = None

while choice != "0":
    print """"High Scores Keeper
    0 - Exit
    1 -Show Scores
    2 - Add A score
    3- Delete a score.
    4- Sort Scores"""
    choice = raw_input("Choice:")
    print 


    if choice == "0":
        print "Good Bye"

    elif choice == "1":
        print "High Scores"
        for score in scores:
            print score

    elif choice == "2":
        score = int(raw_input("What score did you get?:  "))
        scores.append(score) 

例如，当我执行循环并选择 1，而不是打印高分时，循环会再次继续，并且对于两个相同。请帮忙。

Answer 1

scores =[]
choice = None

while choice != "0":
    print """High Scores Keeper
    0- Exit
    1- Show Scores
    2- Add A score
    3- Delete a score.
    4- Sort Scores"""
    choice = raw_input("Choice:")
    if choice == "0":
        print "Good Bye"
    elif choice == "1":
        print "High Scores"
        for score in scores:
            print score
    elif choice == "2":
        score = int(raw_input("What score did you get?:  "))
        scores.append(score)

Answer 2

您对循环进行了编码，以便它在choice != "0" 时继续运行，并且只有在choice == "0" 时才会退出循环。如果你想用"1" 跳出循环，你需要一个对应的循环条件：

while choice != "0" and chioce != "1" and choice != "2" and ...

或者你可以用更简洁的方式来写：

while 0 <= int(choice) and int(choice) <= 4:

while choice not in ["0", "1", "2", "3", "4", "5"]:

#or something like that.