【问题标题】:Check if list contains multiple values android检查列表是否包含多个值android
【发布时间】:2013-02-08 11:15:05
【问题描述】:

我已经搜索到:How to check if a value already exists in the database in Android。我遇到的问题是吐司从不显示,并且当输入的值与数据库中已有的值匹配时,数据仍然输入到数据库中。我看过有关使用 UNIQUE 确保数据不重复的帖子,但它不适用于我需要做的事情。我已经尝试过 if (entries.contains(checkDuplicates) == false) 和 if (!entries.equals(checkDuplicates)),也得到了相同的结果。我知道这是我想念或不理解的简单事情。请有人帮助我并为我指明正确的方向吗?

    private void saveState() {

    Calendar calendar = Calendar.getInstance();
    SimpleDateFormat sdf = new SimpleDateFormat("MM/dd/yyyy");
    eventDate = sdf.format(calendar.getTime());

    String date = eventDate;
    String event = eventTitle.getText().toString();
    String empID = fiveAndTwo.getText().toString();

    /**
     * CRUD Operations
     * */
    // Inserting entries to DB

    // Reading all contacts
    Log.d("Reading: ", "Reading all entries..");

    List<EventEntries> entries = db.getAllEntries();

    for (EventEntries ee : entries) {
        String log = "Id: " + ee.getID() + " Date: " + ee.getDate() + " Event Name: " + ee.getEvent() + " Emp ID: " + ee.getempID();

        // Writing entries to log
        Log.d("Entry: ", log);


    }

    String checkDuplicates =  date + event + empID;

    if (!entries.contains(checkDuplicates)) {

        Log.d("Insert: ", "Inserting ..");

        db.addEntry(new EventEntries(date, event, empID));
        String logEntry = "Date: " + date + " Event Name: " + event + " Emp ID: " + empID;
        Log.d("Entered to DB:", logEntry);

    } else {

        Toast.makeText(this,"Employee has already been scanned for this event.", Toast.LENGTH_SHORT).show();

    }
}

编辑:我让它工作了。这是我所做的:

    private void saveState() {

    Calendar calendar = Calendar.getInstance();
    SimpleDateFormat sdf = new SimpleDateFormat("MM/dd/yyyy");
    eventDate = sdf.format(calendar.getTime());

    String date = eventDate;
    String event = eventTitle.getText().toString();
    String empID = fiveAndTwo.getText().toString();

    /**
     * CRUD Operations
     * */

    // Reading all entries
    Log.d("Reading: ", "Reading all entries..");

    List<EventEntries> entries = db.getAllEntries();

    for (EventEntries ee : entries) {
        String log = "Id: " + ee.getID() + " Date: " + ee.getDate() + " Event Name: " + ee.getEvent() + " Emp ID: " + ee.getempID();

        // Writing entries to log
        Log.d("Entry: ", log);

    }

    EventEntries checkDuplicates = new EventEntries(date, event, empID);

    if (!entries.contains(checkDuplicates)) {

        Toast.makeText(this,"Successfully entered.", Toast.LENGTH_SHORT).show();

        // Inserting entries to DB
        Log.d("Insert: ", "Inserting ..");
        db.addEntry(new EventEntries(date, event, empID));
        String logEntry = "Date: " + date + " Event Name: " + event + " Emp ID: " + empID;
        Log.d("Entered to DB:", logEntry);


    } else  {

        empAlert();

    }
}

这是我添加到 EventEntries 类的内容:

    @Override
public int hashCode() {
    final int prime = 31;
    int result = 1;
    result = prime * result + ((_date == null) ? 0 : _date.hashCode());
    result = prime * result + ((_empID == null) ? 0 : _empID.hashCode());
    result = prime * result + ((_event == null) ? 0 : _event.hashCode());
    return result;
}

@Override
public boolean equals(Object obj) {
    if (this == obj)
        return true;
    if (obj == null)
        return false;
    if (getClass() != obj.getClass())
        return false;
    EventEntries other = (EventEntries) obj;
    if (_date == null) {
        if (other._date != null)
            return false;
    } else if (!_date.equals(other._date))
        return false;
    if (_empID == null) {
        if (other._empID != null)
            return false;
    } else if (!_empID.equals(other._empID))
        return false;
    if (_event == null) {
        if (other._event != null)
            return false;
    } else if (!_event.equals(other._event))
        return false;
    return true;
}

【问题讨论】:

    标签: android


    【解决方案1】:

    entries.contains(checkDuplicates) 总是返回 false,因为 entriesEventEntries 对象的列表,而 checkDuplicatesString。您应该使用EventEntries 对象作为参数调用entries.contains

    还有一件事:

    // assuming entries is not empty
    EventEntries first = entries.get(0);
    entries.contains(first);  // --> this is TRUE
    
    // create a dupe of "first"
    EventEntries firstDupe = new EventEntries(.....);
    entries.contains(firstDupe);  // --> in *general* this is FALSE
    

    一般来说,第二种情况是假的。如果在EventEntries 类中覆盖equals 方法,那么first.equals(firstDupe) 将返回true,这可能是真的。只有这样,第二个例子才会返回 true。

    这是一个示例实现:

    public boolean equals(Object obj) {
        if (obj instanceof EventEntries) {
            EventEntries other = (EventEntries)obj;
            if (date.equals(other.date) && event.equals(other.event)
                && empID == other.empID) {
                return true;
            }
        }
        return false;
    }
    

    (根据需要进行调整。)

    【讨论】:

    • 我尝试了下面的评论但没有成功。我是否需要做一些不同的事情来获取 EventsEntries 对象?
    • 感谢您提供的信息。在你的帮助下我得到了它,我发现 stackoverflow.com/questions/4404084/… 也对我有帮助。
    【解决方案2】:

    替换:

    String checkDuplicates = date + event + empID;

    与:

    EventEntries checkDuplicates = new EventEntries(date, event, empID);

    【讨论】:

    • 我试过了,它仍然不能正常工作。它从不承认信息已经存在。更改为这会使日期、事件和 empID 成为 EventEntries 对象,对吗?请原谅我的无知,我对android、java和面向对象编程还是新手。
    • 感谢您的帮助。我结合了你的答案和上面的答案来让它工作。
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