如何在oracle中加入和计算多个条件

Question

我有 2 张桌子：

table1(id, name)
1233    AAA
3424    BBB
4345    CCC
4342    DDD
1243    RRR
3453    GGG

table2(id,date,status)
1233    01/07/19    1
3424    01/07/19    1
4342    01/07/19    2
1243    01/07/19    1
4342    01/07/19    1
4345    02/07/19    2
1243    02/07/19    1
1233    02/07/19    1
4345    03/07/19    1
4342    03/07/19    2
1233    03/07/19    1
4342    04/07/19    2
4345    04/07/19    2
4342    04/07/19    1
1243    04/07/19    2

15 行

我试过这个代码

SELECT    rn.id, name, NVL(cnt, 0) jum
    FROM     table1 rn
    LEFT JOIN (SELECT   id, COUNT(id) AS cnt
               FROM     VIEW_AKTIFITAS
               WHERE extract(year from date)=2019
               AND extract(month from date)=7
               GROUP BY id,extract(month from date) n ON n.id= rn.id

我想得到这个结果 如何统计表2中的状态条目

RESULT
ID  COUNT_STATUS_1 COUNT_STATUS_2 TOTAL_COUNT
1233    2           0       2
3424    2           0       2
4345    1           2       3 
4342    2           3       5
1243    2           1       3
3453    0           0       0

请帮我解决这个问题..谢谢

Answer 1

这是我的最终代码

SELECT t1.nip, t1.nama_pegawai,
           count(CASE
                   WHEN t2.status = 1 
                    and t2.tahun=2019
              and t2.bulan=7
                   THEN
                     1
                 END) count_status_1,
           count(CASE
                   WHEN t2.status = 2 
                    and t2.tahun=2019
              and t2.bulan=7
                   THEN
                     1
                 END) count_status_2,
           count(CASE
           WHEN  t2.tahun=2019
              and t2.bulan=7
              THEN 1 END
            ) total_count
           FROM VIEW_PEGAWAI t1
                LEFT JOIN VIEW_AKTIFITAS t2
                          ON t2.nip = t1.nip
              where t1.opd_id=14  
              and T1.JENIS_PEG<>3

                          group by t1.nip,t1.nama_pegawai

Answer 2

根据您的示例代码，您似乎想要：

SELECT rn.id, rn.name, NVL(cnt, 0) jum,
       SUM(CASE WHEN a.status = 1 THEN 1 ELSE 0 END) as status_1,
       SUM(CASE WHEN a.status = 1 THEN 1 ELSE 0 END) as status_2,
       COUNT(a.status) as total
FROM table1 rn LEFT JOIN
     VIEW_AKTIFITAS a
     ON a.id = rn.id AND
        a.date >= DATE '2019-07-01' AND
        a.date < DATE '2019-08-01'
GROUP BY rn.id, rn.name;

您不需要LEFT JOIN 的子查询。使用直接日期比较可以更好地完成日期比较。 Oracle 允许您使用带有 DATE 关键字的 ISO 标准日期格式。

Answer 3

在 Oracle 11.1 及更高版本中，您可以使用 PIVOT 运算符进行聚合。像这样的：

select id, name, count_status_1, count_status_2, 
       count_status_1 + count_status_2 as total_count
from   (select t1.id, t1.name, t2.status from table1 t1 left join table2 t2
                                                        on t1.id = t2.id)
pivot  (count(*) for status in (1 as count_status_1, 2 as count_status_2))
order  by id   --  if needed
;

Answer 4

将table2 左连接到table1，然后使用条件聚合来获取两种状态的不同计数。

SELECT t1.id,
       count(CASE
               WHEN t2.status = 1 THEN
                 1
             END) count_status_1,
       count(CASE
               WHEN t2.status = 2 THEN
                 1
             END) count_status_2,
       count(t2.status) total_count
       FROM table1 t1
            LEFT JOIN table2 t2
                      ON t2.id = t1.id;