Python - '函数'对象对于高分表是不可迭代的

Question

我正在尝试创建一个高分表，以相反的顺序列出游戏的高分，并保留前十名。我将它们定义为 2 个函数

我有 2 个问题，

1 - 每次我尝试运行 display_scores 部分时都会收到此错误：

'function' object is not iterable

2 - 当我添加多个分数时，每个分数都会被替换而不是添加到列表中。例如：得分为 8 的 Jim 将在添加另一个分数时被替换。

我可能在这里做一些愚蠢的事情，但我还在学习！

我的代码：

def display_scores():

    print("\n     High Scores\n")
    print("Name", "\t\tScore")
    print("¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯")
    for entry in scores:
        name, score = entry
        print(name, "\t\t", score)




def scores():
    """The High Scores Table."""


    scores = []

    name = input("What is your name?")
    score = score_counter
    entry = (name, score)
    scores.append(entry)
    scores.sort(reverse=True)
    scores = scores[:10]

    print("\n     High Scores\n")
    print("Name", "\t\tScore")
    print("¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯")
    print(name, "\t\t", score)

Answer 1

你必须 1）更改函数的名称和 2) 使分数全球化

scores = []

def display_scores():
    print("\n     High Scores\n")
    print("Name", "\t\tScore")
    print("------------------")
    for entry in scores:
        name, score = entry
        print(name, "\t\t", score)



def scores1():
    """The High Scores Table."""

    global scores 
    name = input("What is your name?")
    score = score_counter
    entry = (name, score)
    scores.append(entry)
    scores.sort(reverse=True)
    scores = scores[:10]

    print("\n     High Scores\n")
    print("Name", "\t\tScore")
    print("--------------")
    print(name, "\t\t", score)