从oracle中的字符串中提取子字符串

Question

我有以下字符串之一：

(,QUESTION-3914~Please enter the unique identification number associated with the IRQ.|3~Greater Than|5~5,AND,QUESTION-3920~Select the contract action that applies to this IRQ.|5~Equal To|LOV1274~New Agreement,),AND,QUESTION-3921~If "New Agreement@comma@" which type of New Agreement is being requested?|5~Equal To|y~Yes,OR,NOT,(,QUESTION-3923~Will the Third Party Relationship support the implementation@comma@ pilot@comma@ launch@comma@ or operation of a New Activity (as defined in the New Activity Risk Management Policy)?|5~Equal To|y~Yes,)

我想要这个字符串所需的输出是这样的：-

(,QUESTION-3914|3|5,AND,QUESTION-3920|5|LOV1274,),AND,QUESTION-3921|5|y,OR,NOT,(,QUESTION-3923)|5|y,)

我该怎么办？

Answer 1

使用正则表达式替换从每个~ 波浪字符到下一个逗号, 或管道| 字符（不包括最后一个字符）的所有内容：

Oracle 设置：

CREATE TABLE your_data ( input_string ) AS
SELECT '(,QUESTION-3914~Please enter the unique identification number associated with the IRQ.|3~Greater Than|5~5,AND,QUESTION-3920~Select the contract action that applies to this IRQ.|5~Equal To|LOV1274~New Agreement,),AND,QUESTION-3921~If "New Agreement@comma@" which type of New Agreement is being requested?|5~Equal To|y~Yes,OR,NOT,(,QUESTION-3923~Will the Third Party Relationship support the implementation@comma@ pilot@comma@ launch@comma@ or operation of a New Activity (as defined in the New Activity Risk Management Policy)?|5~Equal To|y~Yes,)' FROM DUAL

查询：

SELECT REGEXP_REPLACE( input_string, '~.*?([|,])', '\1' ) AS output
FROM   your_data d

输出：

|输出 | | :------------------------------------------------ -------------------------------------------------- | | (,QUESTION-3914|3|5,AND,QUESTION-3920|5|LOV1274,),AND,QUESTION-3921|5|y,OR,NOT,(,QUESTION-3923|5|y,) |

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