与多个收件人一起发送 gmail

Question

我正在尝试创建批量电子邮件发件人。我正在努力添加多个收件人。我希望脚本打开包含多个电子邮件地址的 contacts.csv，并将电子邮件发送给他们。

简单地说，我需要帮助创建一个打开 csv 文件、读取电子邮件并将电子邮件发送到这些地址的脚本。

我试过了，但是没用：

with smtplib.SMTP("smtp.gmail.com:587") as server:
    with open("contacts.csv") as file:
        reader = csv.reader(file)
        next(reader)  # Skip header row
        for name, email in reader:
            server.sendmail(
                sender_email,
                email,text
                #message.format(name=name),
            )

我的 contacts.csv 文件：

name, email
john, test1@gmail.com
jake, test2@gmail.com

我的 emailsender.py 文件：

import smtplib
from email import encoders 
from email.mime.text import MIMEText 
from email.mime.multipart import MIMEMultipart 

fromaddr = "myemail@gmail.com"
toaddr = "emails@gmail.com"
msg = MIMEMultipart() 
      
msg['From'] = fromaddr 
msg['To'] = toaddr 
msg['Subject'] = "test"
body = "testing"
msg.attach(MIMEText(body, 'plain')) 
      
s = smtplib.SMTP('smtp.gmail.com', 587) 
s.starttls() 
s.login(fromaddr, "password") 
text = msg.as_string() 
s.sendmail(fromaddr, toaddr, text)
print("Email sent!")
s.quit() 
send()

Answer 1

我已经测试了这段代码，它工作正常：

import smtplib
from email.mime.text import MIMEText 
from email.mime.multipart import MIMEMultipart 
import csv

emails = []
with open('test.csv', 'r') as file: #open csv file
  reader = csv.reader(file) #init the csv reader
  for row in reader: #iterate through all rows in the csv file
    emails.append(row[1]) #add the second element of every row (the email column) to the list "emails"
  emails.pop(0) #remove the first email which is just the text "email" in the csv file that we don't want
print(emails) #remove if you wish

def sender(recipients, from_email, password, body, subj): #create a sender function. partially adapted from https://stackoverflow.com/a/51931160/8402369
  msg = MIMEMultipart()

  msg['Subject'] = subj
  msg['From'] = from_email
  msg['To'] = (', ').join(recipients)

  msg.attach(MIMEText(body,'plain'))

  server = smtplib.SMTP('smtp.gmail.com', 587)
  server.starttls()
  server.login(from_email, password)
  server.send_message(msg)
  server.quit()


sender(emails, 'youremail@gmail.com', 'your_password', 'Message body', 'Subject') #send all emails

Run and edit the code online

编辑：

这是一个能够根据 csv 数据更改电子邮件内容的版本：

import smtplib
from email.mime.text import MIMEText
from email.mime.multipart import MIMEMultipart
import csv

csvdata = []
with open('test.csv', 'r') as file:  #open csv file
    reader = csv.reader(file)  #init the csv reader
    for row in reader:  #iterate through all rows in the csv file
        csvdata.append(
            row #instead of adding the email to the array, add the whole row to the array
        )  #add the second element of every row (the email column) to the list "emails"
    csvdata.pop(0)


def sender(
        recipient, name_to_display, from_email, password, body, subj
):  #create a sender function. partially adapted from https://stackoverflow.com/a/51931160/8402369
    msg = MIMEMultipart()

    msg['Subject'] = subj
    msg['From'] = f'{name_to_display} <{from_email}>'
    msg['To'] = recipient

    msg.attach(MIMEText(body, 'plain'))

    server = smtplib.SMTP('smtp.gmail.com', 587)
    server.starttls()
    server.login(from_email, password)
    server.send_message(msg)
    server.quit()

your_email = "email@gmail.com"
your_password =  "password"
name_to_display = "The name of the sender that displays in the inbox (your name or whatever you want)"

for item in csvdata:
    name = item[0] #the first column of the csv file is the name
    email = item[1] #the second is the email. if you have more columns get them here like so: item[2] (change the index accordingly)
    print(f'Sending email to {email}')
    body = "Hi " + name + ", The rest of the content goes here"
    subject = "Subject"
    sender(email, name_to_display, your_email, your_password, body, subject)

Run and edit this code online

注意事项：

sender函数部分改编自here