如何在保留列表名称和值的同时展平一列列表？ [r] [重复]答案

【问题标题】：How to flatten a column of lists while keeping list names and values? [r] [duplicate]如何在保留列表名称和值的同时展平一列列表？ [r] [重复]
【发布时间】：2023-12-11 03:17:01
【问题描述】：

我已经阅读了 4-5 个类似的问题，但他们的案例不同，我不知道如何将我阅读的内容应用到我的案例中。

我有一个（公共）数据框，其中最后一列是一个列表：

点击放大镜显示如下结构：

当我unnest() 时，我会丢失度量名称（即visits、hits 等）：

如何在保留指标名称的同时展平该列表？

样本数据：

structure(list(fullVisitorId = c("2248281639583218707", "8647436381089107732", 
"2055839700856389632", "0750846065342433129", "0573427169410921198"
), date = c("20170801", "20170801", "20170801", "20170801", "20170801"
), visitStartTime = c(1501583974L, 1501616585L, 1501583344L, 
1501573386L, 1501651467L), totals = list(list(visits = 1L, hits = 1L, 
    pageviews = 1L, timeOnSite = NA_integer_, bounces = 1L, transactions = NA_integer_, 
    transactionRevenue = NA_integer_, newVisits = 1L, screenviews = NA_integer_, 
    uniqueScreenviews = NA_integer_, timeOnScreen = NA_integer_, 
    totalTransactionRevenue = NA_integer_, sessionQualityDim = 1L), 
    list(visits = 1L, hits = 1L, pageviews = 1L, timeOnSite = NA_integer_, 
        bounces = 1L, transactions = NA_integer_, transactionRevenue = NA_integer_, 
        newVisits = 1L, screenviews = NA_integer_, uniqueScreenviews = NA_integer_, 
        timeOnScreen = NA_integer_, totalTransactionRevenue = NA_integer_, 
        sessionQualityDim = 1L), list(visits = 1L, hits = 1L, 
        pageviews = 1L, timeOnSite = NA_integer_, bounces = 1L, 
        transactions = NA_integer_, transactionRevenue = NA_integer_, 
        newVisits = 1L, screenviews = NA_integer_, uniqueScreenviews = NA_integer_, 
        timeOnScreen = NA_integer_, totalTransactionRevenue = NA_integer_, 
        sessionQualityDim = 1L), list(visits = 1L, hits = 1L, 
        pageviews = 1L, timeOnSite = NA_integer_, bounces = 1L, 
        transactions = NA_integer_, transactionRevenue = NA_integer_, 
        newVisits = 1L, screenviews = NA_integer_, uniqueScreenviews = NA_integer_, 
        timeOnScreen = NA_integer_, totalTransactionRevenue = NA_integer_, 
        sessionQualityDim = 1L), list(visits = 1L, hits = 1L, 
        pageviews = 1L, timeOnSite = NA_integer_, bounces = 1L, 
        transactions = NA_integer_, transactionRevenue = NA_integer_, 
        newVisits = NA_integer_, screenviews = NA_integer_, uniqueScreenviews = NA_integer_, 
        timeOnScreen = NA_integer_, totalTransactionRevenue = NA_integer_, 
        sessionQualityDim = 1L))), row.names = c(NA, -5L), class = c("tbl_df", 
"tbl", "data.frame"))

【问题讨论】：

cbind(df[-4], do.call(rbind.data.frame, df$totals)) 呢？
谢谢@RuiBarradas！这在样本数据上效果很好，但有更快的选择吗？实际数据有数百万行 =\.

标签： r list dataframe tidyr flatten

【解决方案1】：

tidyr::unnest_wider()是你想要的吗？

tidyr::unnest_wider(sample_data,totals)

# A tibble: 5 x 16
  fullVisitorId date  visitStartTime visits  hits pageviews timeOnSite bounces transactions transactionReve~ newVisits screenviews
  <chr>         <chr>          <int>  <int> <int>     <int>      <int>   <int>        <int>            <int>     <int>       <int>
1 224828163958~ 2017~     1501583974      1     1         1         NA       1           NA               NA         1          NA
2 864743638108~ 2017~     1501616585      1     1         1         NA       1           NA               NA         1          NA
3 205583970085~ 2017~     1501583344      1     1         1         NA       1           NA               NA         1          NA
4 075084606534~ 2017~     1501573386      1     1         1         NA       1           NA               NA         1          NA
5 057342716941~ 2017~     1501651467      1     1         1         NA       1           NA               NA        NA          NA
# ... with 4 more variables: uniqueScreenviews <int>, timeOnScreen <int>, totalTransactionRevenue <int>, sessionQualityDim <int>

【讨论】：