Laravel 单元测试控制器

Question

如何测试具有 __construct 的函数？

例如，我的控制器代码如下所示：

    namespace App\Http\Controllers; 
    use App\Repositories\UserAccountRepository;
    class UserController extends ProtectedController
    {
      protected $userAccountRepository;
      public function __construct(userAccountRepository 
      $userAccountRepository){
        parent::__construct();
        $this->userAccountRepository = $userAccountRepository;
    }

    public function FunctionWantToTest(){
        return 'string';
    }

在测试我的 FunctionWantToTest 之前首先完成构造所需的单元测试。

所以，我的测试代码看起来像，

use Illuminate\Foundation\Testing\WithoutMiddleware;
use Illuminate\Foundation\Testing\DatabaseMigrations;
use Illuminate\Foundation\Testing\DatabaseTransactions;
use App\Http\Controllers\UserController;

class UserTest extends TestCase
{
    /**
     * A basic test example.
     *
     * @return void
     */
    public function testUserList()
    {

        $UserController = new UserController(???what value??);
        $this->assertTrue(true);
    }
}

需要更多帮助（最佳实践）如何测试具有构造的代码。

Answer 1

测试控制器时使用功能测试或集成测试，

您可以看到有关单元测试和集成测试的简要说明。

What's the difference between unit tests and integration tests?

Answer 2

我想你只需要使用app->make:

class UserTest extends TestCase
{

    protected $userController;

    public function setUp() {

        parent::setUp();

        $this->userController = $this->app->make(UserController::class);
    }

    /**
     * A basic test example.
     *
     * @return void
     */
    public function testUserList()
    {
        $this->userController // do what you need here...
        $this->assertTrue(true);
    }
}