如何使 laravel 路由失败以进行单元测试？

Question

我的控制器中有以下代码

public function store(CreateSpecialityRequest $request) 
{
    DB::beginTransaction();
    try {
        $speciality = $this->specialityRepository->create($request->all());
        DB::commit();

        return redirect()->route('specialities.index')
            ->with('success', 'Speciality Added successfully');
    } catch (\Exception $e) {
        DB::rollBack();
        return $e->getMessage();
        return redirect()->route('specialities.index')
            ->with('error', 'Specialities details updating failed');
    }

}

我的测试用例

$speciality = [
            'name' => $faker->name,
            'description' => $faker->sentence,
            'icon' => $uploadedFile
        ];

        $this->post('/specialities', $speciality)
            ->assertResponseStatus(302)
            ->assertRedirectedToRoute('specialities.index')
            ->assertSessionHas(['success' => 'Speciality Added successfully'])
            ->followRedirects()
            ->assertViewHas('specialities');

在我的代码覆盖率上，它表明我只覆盖了 try 块 我也想覆盖 catch 块。如何在单元测试中失败我的路线？进入 catch 块

Answer 1

您可以只传递一个空数组作为输入，create 方法应该抛出 QueryException。

$this->post('/specialities', []);

您还应该查看您的 catch 块返回。您将立即返回异常消息，永远不会调用带有消息的重定向。

return $e->getMessage();
return redirect()->route('specialities.index')
            ->with('error', 'Specialities details updating failed');