Laravel 关系设计

Question

我正在从事团队管理项目。 我在处理人际关系方面有问题。

我想在看板中显示用户，但也希望看起来美观且易于阅读。我已经设计了关系，但是当我看到关系的 JSON 输出时，它完全一团糟。

有没有办法以这种方式显示关系数据？

{
    "id": 1,
    "name: "Test",
    "members": [
        {
            ... user model here
            "name": "Peter",
            "email": "peter@peter.com",
        }
    ]
}

我的迁移：

板迁移

<?php

use Illuminate\Support\Facades\Schema;
use Illuminate\Database\Schema\Blueprint;
use Illuminate\Database\Migrations\Migration;

class CreateBoardsTable extends Migration
{
    /**
     * Run the migrations.
     *
     * @return void
     */
    public function up()
    {
        Schema::create('boards', function (Blueprint $table) {
            $table->increments('id');
            $table->string('name');
            $table->timestamps();
        });
    }

    /**
     * Reverse the migrations.
     *
     * @return void
     */
    public function down()
    {
        Schema::dropIfExists('boards');
    }
}

会员迁移

<?php

use Illuminate\Support\Facades\Schema;
use Illuminate\Database\Schema\Blueprint;
use Illuminate\Database\Migrations\Migration;

class CreateMembershipsTable extends Migration
{
    /**
     * Run the migrations.
     *
     * @return void
     */
    public function up()
    {
        Schema::create('memberships', function (Blueprint $table) {
            $table->increments('id');
            $table->integer('board_id')->unsigned();
            $table->integer('user_id')->unsigned();
            $table->timestamps();
        });
    }

    /**
     * Reverse the migrations.
     *
     * @return void
     */
    public function down()
    {
        Schema::dropIfExists('memberships');
    }

}

编辑：

型号

<?php

namespace App;

use Illuminate\Database\Eloquent\Model;

class Board extends Model
{
    protected $fillable = ['name'];

    public function members() {
        return $this->hasMany(Membership::class)->with('user');
    }
}

<?php

namespace App;

use Illuminate\Database\Eloquent\Model;

class Membership extends Model
{
    protected $fillable = ['board_id', 'user_id'];
    protected $hidden = ['created_at', 'updated_at'];

    public function user() {
        return $this->hasOne(User::class, 'id', 'user_id');
    }
}

Answer 1

您可以尝试将模型中的关系定义为多对多，即：

class User
{    
    public function boards()
    {
        return $this->belongsToMany('App\Board', 'memberships', 'user_id', 'board_id');
    }
}

class Board
{    
    public function members()
    {
        return $this->belongsToMany('App\User', 'memberships', 'board_id', 'user_id');
    }
}

定义了关系后，如果没有附加字段，您就不需要成员模型，您可以编写如下代码：

User::find($id)->boards
Board::find($id)->members
Board::with('members')->find($id)

您还可以阅读 Many to Many Relationships 上的文档