Laravel 验证：required_if 中的规则

Question

我有一个选择列表，其中第一个选项被禁用，这就是当用户没有选择有效选项时，选择列表的结果不会出现在请求中。

在验证中，必填字段，如果其他字段的值为例如：1, in case not 1, the field is not required。

代码：

'city_id' => [
'required',
'integer',
Rule::in(City::availableCities()),
],
'district_id' => new DistrictValidation(request('city_id')),

我怎么能做到这一点，district_id 每次都会抛出验证，不管它是否在请求中。

感谢您的回答，

更新： 也许你看清楚了，如果 DistrictValidation 规则在这里：

class DistrictValidation implements Rule
{
    protected $city;
    private $messages;

    /**
     * Create a new rule instance.
     *
     * @param $cityId
     */
    public function __construct($cityId)
    {
        $this->city = City::find($cityId);
    }

    /**
     * Determine if the validation rule passes.
     *
     * @param  string  $attribute
     * @param  mixed  $value
     * @return bool
     */
    public function passes($attribute, $value)
    {
        dd('here');
        if (!$this->city) {
            return false;
        }

        if (!$this->city->hasDistrict) {
            return true;
        }

        $validator = Validator::make([$attribute => $value], [
            $attribute => [
                'required',
                'integer',
                Rule::in(District::availableDistricts()),
            ]
        ]);

        $this->messages = $validator->messages();

        return $validator->passes();
    }
    /**
     * Get the validation error message.
     *
     * @return string
     */
    public function message()
    {
       return optional($this->messages)->first('district_id');
    }
}

Answer 1

试试这个：

'city_id' => [
  'nullable',
  'numeric',
  Rule::in(City::availableCities())
],
'district_id' => new DistrictValidation(request('city_id')),

Answer 2

试试这个：

$myValidations = [
    "city_id" => [
        "required",
        "integer"
    ]
]

// if city_id exists in availableCities so add some rules 
if(collect(city::availableCities)->contains(request("city_id"))){
    $myValidations["district_id"] = new DistrictValidation(request('city_id'))
}

// validate request fields with $myValidations variable

Answer 3

尝试使用required_if 验证，如果另一个字段字段等于任何值，则验证中的字段必须存在且不能为空。

required_if:field,value,...

像这样使用它：

$request->validate([ 'city_id' => 'required|integer|Rule::in(City::availableCities())', 'district_id' => 'required_if:city_id,1', ]);

尝试阅读更多laravel验证here

Answer 4

你可以使用 laravel 验证中定义的 required_if 条件 这是正确文档的链接Laravel Validation

Validator::make($data, [
    'city_id' => [
        'required',
        'integer',
        Rule::in(City::availableCities()),
    ],
    'district_id'=>[
         'required_with:city_id,',
    ]
]);