Laravel group by 内联选择语句的问题答案

【问题标题】：Laravel group by issues with an inline select statementLaravel group by 内联选择语句的问题
【发布时间】：2019-12-22 16:56:29
【问题描述】：

下面的 SQL 工作正常。它正在采用这个并在问题所在的 Laravel 中实现它。 sqlfiddle 可以在here 找到。

SELECT provider_id
     , o.shortName
     , count(b.site_id) as sites
     , ( select b.depositFee 
              + ( select sum(depositFee) 
                    from backhaul 
                   where backhaul.parent_id=b.id
                ) 
       ) as entranceFee
     , ( select b.rightOfWayCharges 
              + ( select sum(rightOfWayCharges) 
                    from backhaul 
                   where backhaul.parent_id = b.id
                )
       ) as rowFee
    FROM backhaul AS b
    JOIN organisation AS o  
      ON (b.provider_id = o.id)
   WHERE isnull(b.parent_id)
   GROUP 
      BY provider_id
       , entranceFee
       , rowFee

表格是递归的。这给了我以下结果：

--------------------------------------------------------
provider_id | sshortName | sites | entranceFee | rowFee
--------------------------------------------------------
802 | TM | 1 | 12500.00 | 7500.00  
803 | TIME | 1 | 7500.00 | 0.00

问题是 Laravel 似乎无法识别 group by 语句中的“entranceFee”或“rowFee”列。

我的 Lararvel 5.7 实现如下所示：

$sql = DB::raw("provider_id, o.shortName, count(b.site_id) as sites," .
"(select b.depositFee + (select sum(depositFee) from backhaul where backhaul.parent_id=b.id)) as entranceFee," .
"(select b.rightOfWayCharges + (select sum(rightOfWayCharges) from backhaul where backhaul.parent_id=b.id)) as rowFee") ;

$data = DB::table("backhaul as b")->select($sql)
   ->join("organisation as o", "b.provider_id", "=", "o.id")
   ->whereNull("b.parent_id")
   ->groupBy("b.provider_id", DB::raw("entranceFee"), DB::raw("rowFee"))
   ->paginate() ;

由于 GROUP BY 语句中缺少 SELECT #4 的错误，我得到了通常的 MySQL 组。

我已尝试将 groupBy(["provider_id", DB::raw("entranceFee"), DB::raw("rowFee")]) 添加为数组，但仍然失败。如果我也添加内联 SQL 选择，它会出错。

【问题讨论】：

标签： php mysql laravel laravel-5 eloquent

【解决方案1】：

Tray2 在Laracasts 上回答了这个问题：

确认以下解决方案有效：

$data = DB::select('SELECT provider_id
     , o.shortName
     , count(b.site_id) as sites
     , ( select b.depositFee 
              + ( select sum(depositFee) 
                    from backhaul 
                   where backhaul.parent_id=b.id
                ) 
       ) as entranceFee
     , ( select b.rightOfWayCharges 
              + ( select sum(rightOfWayCharges) 
                    from backhaul 
                   where backhaul.parent_id = b.id
                )
       ) as rowFee
    FROM backhaul AS b
    JOIN organisation AS o  
      ON (b.provider_id = o.id)
   WHERE isnull(b.parent_id)
   GROUP 
      BY provider_id
       , entranceFee
       , rowFee');

【讨论】：

【解决方案2】：

Laravel 很可能将它们包装在反引号中，这会导致 MySQL 相信它们是某个表中的实际列。也可以尝试将它们包装在 DB::raw 中。

$data = DB::table("backhaul as b")->select($sql)
    ->join("organisation as o", "b.provider_id", "=", "o.id")
    ->whereNull("b.parent_id")
    ->groupBy([
        "b.provider_id",
        \DB::raw('entranceFee'),
        \DB::raw('rowFee'),
    ])
    ->paginate() ;

【讨论】：

感谢 user1669496，我试过了。但是，我现在得到：Unknown column 'entranceFee' in 'group statement'。从输出中，DB::raw 确实删除了反引号。
我尝试将整个子选择 SQL 放入 group by （在其他情况下我不得不这样做）但是因为 SUM() MySQL 中的 SUM() 操作正确发疯了。