【发布时间】:2015-01-22 19:48:30
【问题描述】:
您好,很高兴我想为我的文本字段使用自定义验证规则:
{{Form::label('password', 'Wachtwoord: ', array('class' => 'col-xs-4'))}}
<div class="col-xs-2">{{ Form::password('password', array('class' => 'form-control', 'placeholder'=>'Password')) }}</div>
我已经按照以下链接的说明进行操作:http://laravel.com/docs/4.2/validation#custom-validation-rules
但是当我想使用我的自定义验证时我卡住了。我认为我的代码做错了。
很高兴我想为我的密码文本字段使用 validatePassword() 方法(在 validation.php 中)。
这是我的 UserController.php:
public function update($id)
{
$user_old_data = User::find($id);
$input_password = Input::get('password');
Validator::resolver(function($translator, $data, $rules, $messages)
{
return new validation($translator, $data, $rules, $messages);
});
/*Validator::extend('validatePassword', function($input_passwords,$input_passwords){
});*/
/*$validator = Validator::make($data = $thisUser, User::$rules);
if ($validator->passes()) {
if($user_old_data['email'] != $new_email){
$email_exists = User::FindEmailOrFail2(Input::get('email') );
if($email_exists)
return Redirect::back()->withErrors($validator)->withInput();
}
//maak message variabel aan in je user index view.
return Redirect::to('user/users')->with('message', 'Update with new password succesfull');
} */
return Redirect::back()->withErrors($validator)->withInput();
}
这是我的validation.php:
<?php
// app/validators/validation.php
class validation extends Illuminate\Validation\Validator
{
public function validateFoo($attribute, $value, $parameters){
//return $value == 'foo';
echo "this is the: " . $value;
}
//{4,} will match strings of length 4 or more.
protected function validatePassword( $attribute, $value ) {
return (bool) preg_match('/^[a-z]{4,}+$/', $value);
die('test');
}
}
【问题讨论】:
标签: php html validation laravel blade