碳得到一年的季度答案

【问题标题】：Carbon get quarter of the year碳得到一年的季度
【发布时间】：2022-01-13 02:30:05
【问题描述】：

我想获得基于季度的数据，因此每年我将有 4 个变量，例如 pastYearsQOne pastYearsQTwo pastYearsQThree pastYearsQFour。

我的问题是如何获得一年中的季度？

code

$pastYearsQOne = Project::orderby('id', 'desc')->whereDate(
  'created_at', '<=', now()->subYear(1)->startOfQuarter()->toDateTimeString()
                                         ^^^^^^^^^^^^^^^^
)->count();

如果仍然没有得到它！这是逻辑，

最终结果会是这样的：

$pastYearsQOne = data of: 2020 (year) -> 01~03 (months)

$pastYearsQTwo = data of: 2020 (year) -> 04~06 (months)

$pastYearsQThree = data of: 2020 (year) -> 07~09 (months)

$pastYearsQFour = data of: 2020 (year) -> 10~12 (months)

【问题讨论】：

标签： php laravel php-carbon carbon

【解决方案1】：

startOfQuarter 和 endOfQuarter 季度非常有用，还有 month 函数。

请尝试使用以下代码。

$startOfQ1 = Carbon::now()->subYear()->month(1)->startOfQuarter();
$endOfQ1 = Carbon::now()->subYear()->month(1)->endOfQuarter();

$startOfQ2 = Carbon::now()->subYear()->month(4)->startOfQuarter();
$endOfQ2 = Carbon::now()->subYear()->month(4)->endOfQuarter();

$startOfQ3 = Carbon::now()->subYear()->month(7)->startOfQuarter();
$endOfQ3 = Carbon::now()->subYear()->month(7)->endOfQuarter();

$startOfQ4 = Carbon::now()->subYear()->month(10)->startOfQuarter();
$endOfQ4 = Carbon::now()->subYear()->month(10)->endOfQuarter();

【讨论】：

谢谢，它帮助我解决了我的问题，这是我的最终代码$pastYearsQOne = Project::orderby('id', 'desc')->whereBetween( 'created_at', [Carbon::now()->subYear(1)->month(1)->startOfQuarter(), Carbon::now()->subYear(1)->month(3)->endOfQuarter()] )->count();

【解决方案2】：

您可以为当前年份添加一个变量Carbon::today() 然后递归地为所有季度添加 3 个月 Carbon::addMonths(3)

【讨论】：

【解决方案3】：

这是你的意思吗？

public function index()
{
    $now = Carbon::now()->subYears(1)->format('Y-m-d H:i:s');

    $pastQuarterOneStart = Carbon::parse($now)->subQuarters(3)->startOfQuarter()->format('Y-m-d H:i:s'); // 2020-01-01 00:00:00
    $pastQuarterOneEnd = Carbon::parse($now)->subQuarters(3)->endOfQuarter()->format('Y-m-d H:i:s'); // 2020-03-31 23:59:59

    $pastQuarterTwoStart = Carbon::parse($now)->subQuarters(2)->startOfQuarter()->format('Y-m-d H:i:s'); // 2020-04-01 00:00:00
    $pastQuarterTwoEnd = Carbon::parse($now)->subQuarters(2)->endOfQuarter()->format('Y-m-d H:i:s'); // 2020-06-30 23:59:59

    $pastQuarterThreeStart = Carbon::parse($now)->subQuarter(1)->startOfQuarter()->format('Y-m-d H:i:s'); // 2020-07-01 00:00:00
    $pastQuarterThreeEnd = Carbon::parse($now)->subQuarter(1)->endOfQuarter()->format('Y-m-d H:i:s'); // 2020-09-30 23:59:59

    $pastQuarterFourStart = Carbon::parse($now)->startOfQuarter()->format('Y-m-d H:i:s'); // 2020-10-01 00:00:00
    $pastQuarterFourEnd = Carbon::parse($now)->->endOfQuarter()->format('Y-m-d H:i:s'); // 2020-12-30 23:59:59


    // Get 2020-01-01 00:00:00 to 2020-03-31 23:59:59
    $pastYearsQOne = Project::orderby('id', 'desc')->whereBetween(
        'created_at',
        [
            $pastQuarterOneStart,
            $pastQuarterOneEnd
        ]
    )->count();

    // Get 2020-04-01 00:00:00 to 2020-06-31 23:59:59
    $pastYearsQTwo = Project::orderby('id', 'desc')->whereBetween(
        'created_at',
        [
            $pastQuarterTwoStart,
            $pastQuarterTwoEnd
        ]
    )->count();

    // Get 2020-07-01 00:00:00 to 2020-09-31 23:59:59
    $pastYearsQThree = Project::orderby('id', 'desc')->whereBetween(
        'created_at',
        [
            $pastQuarterThreeStart,
            $pastQuarterThreeEnd
        ]
    )->count();

    // Get 2020-10-01 00:00:00 to 2020-12-31 23:59:59
    $pastYearsQFour = Project::orderby('id', 'desc')->whereBetween(
        'created_at',
        [
            $pastQuarterFourStart,
            $pastQuarterFourEnd
        ]
    )->count();
}

这里我也根据你要检索的数据更改查询。

【讨论】：