【发布时间】：2021-07-18 11:56:19
【问题描述】：
我已经working on a Python tic-tac-toe game 大约一个月了，终于看到了结局。我正在为游戏的代码而苦苦挣扎，非常感谢任何人为克服这个障碍而提出的建议。
问题：
每次玩家移动时，我的 game_board 都会重新打印一次。因此，游戏在任何一个棋盘被填满之前就结束了。
代码
这是我的游戏板的代码：
game_board = ['#'] + ([' ']*9)
display_board(game_board)
这是我的游戏代码：
print('Welcome to Tic Tac Toe!')
# turn = '' # needs to be an empty string because we're storing the result of go_first(), a string, inside
while True: # loop forever
game_board = [' ']*10 # clear board
player1_marker , player2_marker = assign_marker() # assign players to marker
turn = go_first() # randomly choose who goes first
print(f"{turn}, you're up first!")
play_game = input("Ready? Enter Yes or No.")
if play_game.lower()[0] == 'y':
game_on = True
else:
game_on = False
while game_on: # initiates the start of the game
if turn == 'Player 1': # if player 1 is first
position = player_choice(game_board) # ask for position from player
place_marker(game_board, player1_marker, position) # place marker at the position
display_board(game_board) # display board
if check_winner(game_board, player1_marker): # if there are no more moves
game_on = False
print(f"{turn} wins!")
else: # if there's no winner
if is_board_full(game_board): # check to see if the board is full
# if board is full but there's no winner, it's a draw
print("It's a draw!")
break
else: # if the board is NOT full ...
turn = 'Player 2' #move on to player 2; THIS IS HOW TO ALTERNATE TURNS
else: # if player 2 is first
position = player_choice(game_board) # ask for position from player
place_marker(game_board, player2_marker, position) # place marker at the position
display_board(game_board)
if check_winner(game_board, player2_marker):
game_on = False
print(f"{turn} wins!")
else: # if there's no winner
if is_board_full(game_board): # check to see if the board is full
# if board is full but there's no winner, it's a draw
game_on = False
print("It's a draw!")
break
else: # if the board is NOT full ...
turn = 'Player 1' #move on to player 2; THIS IS HOW TO ALTERNATE TURNS
if not replay():
break
结果
Welcome to Tic Tac Toe!
Player 1 has chosen X
Player 2 is O
Player 1, you're up first!
| |
| |
_____
| |
| |
_____
| |
| |X
| |
| |
_____
| |
|O|
_____
| |
| |X
| |
X| |
_____
| |
|O|
_____
| |
| |X
| |
X|O|
_____
| |
|O|
_____
| |
| |X
| |
X|O|X
_____
| |
|O|
_____
| |
| |X
| |
X|O|X
_____
| |
|O|
_____
| |
|O|X
Player 2 wins!
---------------------------------------------------------------------------
IndexError Traceback (most recent call last)
<ipython-input-36-9859c5aad566> in <module>
54 turn = 'Player 1' #move on to player 2; THIS IS HOW TO ALTERNATE TURNS
55
---> 56 if not replay():
57 break
<ipython-input-30-73127fbca36c> in replay()
9 choice = input("Do you want to play again? ") # program will keep asking for valid input
10
---> 11 if choice.lower()[0] == 'n':
12 print("GAME OVER.")
13 return False
IndexError: string index out of range
而且，这与 IndexError 相关：
def replay():
choice = ' '
# declare variable, which is an empty string
while choice.lower()[0] != 'y': #uppercasing the 'Y' ensures that input can only be uppercase
# while loop ensures any other input will be rejected
choice = input("Do you want to play again? ") # program will keep asking for valid input
if choice.lower()[0] == 'n':
print("GAME OVER.")
return False
else:
print("LET'S PLAY!")
return True
# if player wants a replay, return a boolean True
对我的代码为什么不起作用有任何猜测吗？
我希望这是足够的代码来告知人们可能有的任何响应。我很乐意分享更多代码。
另外，我理解是否有些人会觉得 StackOverflow 不适合提出此类问题。我只是想学习和解决问题！提前致谢！
【问题讨论】：
-
检查是否
choice > 0怎么样？就像if len(choice) < 1: choice = ' '; continue直接在input之后？然后它会再次询问选择是否为空。 -
感谢您的回答，@wuerfelfreak！虽然这个解决方案对我不起作用，但我设法自己解决了这个问题。
标签： python tic-tac-toe