将字符串数组转换为 if else 条件的字符串

Question

我正在努力学习，（我是编码新手）

这是我写的

static void Main(string[] args)
{
    string username = "James";
    string[] Userclass = new string[3] { "Mage", "Warrior", "Assasin" };

    Console.WriteLine("What class will you be? You can choose from Mage, Warrior, Or Assasin: ");


    if (Userclass.Contains("Mage"))
    {
        String Message = "You are a strong Willed Mage " + username;
        Console.WriteLine(Message);
    }
     if (Userclass.Contains("Warrior"))
    {
        String Message = "Your are a valiant Warrior " + username;
        Console.WriteLine(Message);
    }
     if (Userclass.Contains("Assasin"))
    {
        String Message = "You are a vigilant Assasin " + username;
        Console.WriteLine(Message);

    }
    Console.ReadLine();
}

但是，如果我定义：

string Userclass = Console.Readline(); 

我得到它的错误

无法将字符串[] 转换为字符串

感谢您的帮助！

Answer 1

好的，有几件事：

您的UserClass 是array。它将保存项目，但除非您附加到它，否则您不能将用户输入写入它。 Here 是来自 MSDN 的 C# 中 Arrays 的引用。

您在string array 上使用.Contains() 而不是string。从逻辑上讲，是的，string array 确实 包含这些值。虽然，如果它实际运行/编译，所有 if statements 将运行 true 而不是从用户输入中选择。

这让我想到了我的下一件事——你要求user input，但实际上从未在所示的Main() 方法中允许它。最常见的方式（我见过）是这样的：

string input = Console.ReadLine();

哪个，我看到您正在尝试实施，所以这不是问题 :)

---

此代码应该适用（我将分解我的更改）：

static void Main(string[] args)
{
    string userName = "James";
    string[] userClass = new string[3] { "mage", "warrior", "assassin" };

    Console.WriteLine("What class will you be? You can choose from Mage, Warrior or Assassin:");
    string input = Console.ReadLine();

    if (input.ToLower() == userClass[0])
    {
        string Message = "You are a strong Willed Mage " + userName;
        Console.WriteLine(Message);
    }
    else if (input.ToLower() == userClass[1])
    {
        string Message = "Your are a valiant Warrior " + userName;
        Console.WriteLine(Message);
    }
    else if (input.ToLower() == userClass[2])
    {
        string Message = "You are a vigilant Assassin " + userName;
        Console.WriteLine(Message);
    }
    else
        Console.WriteLine("No proper class selected...");

    Console.ReadLine();
}

string userName 与您的string[] userClass 保持不变（我已将大写更改为驼峰式）。只要您正确检查array，将这些userClasss 存储在array 中就没有问题（我看到）。

而不是检查string[] userClass 数组是否包含这些项目，因为我们知道它会按照我们编写的方式执行并且如前所述，它总是会运行true。相反，我们检查user input 是否匹配数组中的某些内容。

我创建了string input = Console.ReadLine() 以允许用户输入，然后我检查input 与string[] userClass 值。我添加了.ToLower() 并将数组值更改为全部小写。这样，如果用户输入 mAgE 而不是 Mage ，就不会抛出错误。

---

如果您想避免使用array，另一种方法是使用switch：

switch (input.ToLower())
{
    case "mage":
        Console.WriteLine($"You are a strong Willed Mage {userName}");
        //assign user class
        break;
    case "warrior":
        Console.WriteLine($"Your are a valiant Warrior {userName}");
        //assign user class
        break;
    case "assassin":
        Console.WriteLine($"You are a vigilant Assasin {userName}");
        //assign user class
        break;
}

Answer 2

给你，我写了 cmets 解释程序的每个部分，如果你有什么不明白的地方，请告诉我。

static void Main(string[] args)
{
    Console.Write("Enter Username: "); // we ask for the username here, you can do it with Console.WriteLine() as well
    string username  = Console.ReadLine();  // get the username
    Console.Write("What class will you be? You can choose from Mage, Warrior, Or Assasin: "); // ask for the class, also same as above, you can use Console.WriteLine()
    string userclass = Console.ReadLine();   // get the class

    // Possible character classes (we use this as a reference to check the class the user gives us later)
    // also set the string representing each class as lower case characters to avoid looping or unnecessary string concatenation later
    string[] charClasses = new string[3] { "mage", "warrior", "assasin" }; // make sure the class given is within our possible character classes

    // here we check that the class given is within the bound of our possible classes and convert
    // the userclass to its lower case equivalent to match it with those in the array
    if (Array.IndexOf(charClasses, userclass.ToLower()) != -1)   
    {
         // if the class is acceptable then attach it to the message along with the username via string concatenation
        String Message = "You are a strong Willed "+userclass + " " + username; 
        Console.WriteLine(Message);  // print the message
    }
}