'else if' 语句总是返回 true

Question

每当我运行这个程序第 69 行的 else if (room == 6) 语句时，它总是返回 true，不管房间的值是多少。

import java.util.Scanner;

public class AdventureTwo {
    public static void main(String[] args) {
        Scanner keyboard = new Scanner(System.in);
        String choice = "";
        int room = 1;

        while (room != 0) {
            if (room == 1) {
                System.out.println("You find yourself in a room. There's a \"blue\" door and a \"red\" door.\nWhich do you choose?");
                choice = keyboard.next();

                if (choice.equalsIgnoreCase("red")) {
                    room = 2;
                } else if (choice.equalsIgnoreCase("blue")) {
                    room = 3;
                }
            } else if (room == 2) {
                System.out.println("Going through the red door reveals the \"family\" room.\nYou can also go \"back\". What is your choice?");
                choice = keyboard.next();
                if (choice.equalsIgnoreCase("family")) {
                    room = 4;
                } else if (choice.equalsIgnoreCase("back")) {
                    room = 1;
                }
            } else if (room == 3) {
                System.out.println("You find two new rooms, the \"kitchen\" and the \"bathroom\".\nYou can also go \"back\", What is your choice?");
                choice = keyboard.next();
                if (choice.equalsIgnoreCase("kitchen")) {
                    room = 5;
                } else if (choice.equalsIgnoreCase("bathroom")) {
                    room = 6;
                } else if (choice.equalsIgnoreCase("back")) {
                    room = 1;
                }
            } else if (room == 4) {
                System.out.println("In the family room you see a tv \"remote\" do you pick it up and turn on the tv, or go \"back\"?");
                choice = keyboard.next();
                if (choice.equalsIgnoreCase("remote")) {
                    System.out.println("You pick up the remote and turn on the tv. You are immediately engrossed in the rv program.");
                    System.out.println("In fact you are so interested you stay there watching tv until you die of dehydration");
                    room = 0;
                } else if (choice.equalsIgnoreCase("back")) {
                    room = 2;
                }
            } else if (room == 5) {
                System.out.println("In the kitchen you find some \"crackers\", you are pretty hungry and they don't look that old.\nYou can also go \"back\".");
                if (choice.equalsIgnoreCase("crackers")) {
                    System.out.println("After eating one cracker, you feel the need to have another one, and another , and another, this goes on until you\nhave eaten so much your stomach bursts and you die.");
                    room = 0;
                } else if (choice.equalsIgnoreCase("back")) {
                    room = 3;
                }
            } else if (room == 6) { // line 69
                System.out.println("In the bathroom there is an open \"window\", you can also go \"back\". What is your choice?");
                choice = keyboard.next();
                if (choice.equalsIgnoreCase("window")) {
                    System.out.println("You climb out the window and drop to the ground. You are free!");
                    room = 0;
                } else if (choice.equalsIgnoreCase("back")) {
                    room = 3;
                }
            }
        }
        System.out.print("Game Over.");
    }
}

Answer 1

我看到你正在改变一些 else-if 中的房间值。这可能会干扰后续的 else-if 块吗？尝试使用 switch...case 语句。

示例：

而（房间！= 0）{
    开关（房间）{

        情况1： {
            System.out.println("你发现自己在一个房间里。有一个\"蓝色\"门和一个\"红色\"门。\n你选择哪个？");
            选择 = 键盘.next();

            if (choice.equalsIgnoreCase("red")) {
                房间 = 2;
            } else if (choice.equalsIgnoreCase("blue")) {
                房间 = 3;
            }
            休息;
        }

        案例2：{
            //房间==2 代码
            休息;
        }

        案例 3：{
            //等等...
            休息; //不要忘记在每个case的右括号前加上“break”
        }
    }
}

第 :-)

Answer 2

您可以创建单独的方法来处理每个房间中发生的事情，然后拥有这些方法的数组或 ArrayList（例如，称为“roomMethod”）。这些方法中的每一个都返回用户选择的下一个房间。那么主要代码是：

  while (room != 0 ) {
    room = roomMethod[room]();
  }