Laravel 6用不同的where子句查询同一张表

Question

我有campaign_report这样的表

Schema::create('campaign_report', function (Blueprint $table) {
    $table->bigIncrements('id');
    $table->date('report_date');
    $table->bigInteger('user_id');
    $table->bigInteger('campaignId');
    $table->double('cost',12,2);
    $table->timestamps();
});

我正在尝试获取昨天的所有活动报告。

        $campaignReports = CampaignReport::where(['report_date' => "$yesterday", 'user_id' => Auth::user()->id])->orderBy('report_date', 'desc')->paginate(25);

以上查询返回所有 report_date 等于 $yesterday 的广告系列。

除了这个查询，我还想获取每个活动的cost 值，其中report_date 是前天匹配campaignId 列。我想显示昨天的广告系列和前天的广告系列之间cost 的区别。

喜欢

foreach($campaignReports as $campaignReport)
{
    $difference = $campaignReport->cost - $campaignReport->dayBeforeYesterdayCost; 
}

谁能帮助我使用 Query Builder 或 Eloquent 构建这个查询？

Answer 1

您可以在 CampaignReport 模型中编写一个关系，计算昨天和前一天的成本之间的差异

public function dayBeforeYesterdayCost() {
     $dayBeforeYesterday = Carbon::parse($this->report_date)->subDays(1); //return date of day before yesterday

     $dayBeforeYesterdayCost = CampaignReport::where('campaignId', $this->campaignId)
     ->where('report_date', $dayBeforeYesterday)
     ->first();

     return $dayBeforeYesterdayCost ? $dayBeforeYesterdayCost->cost : 0;
}


public function lastDayDifference() {
     $difference = $this->cost - $this->dayBeforeYesterdayCost; 
     return $difference;
}

现在您可以像这样返回 $campaignReports 和 lastDayDifference 关系：

 $campaignReports = CampaignReport::where(['report_date' => "$yesterday", 'user_id' => Auth::user()->id])
->with('lastDayDifference')
->orderBy('report_date', 'desc')
->paginate(25);

最后，您的每一个$campaignReport 都附加了一个对象

Answer 2

按日期分组（report_date），它只会给你日期部分，按相同的降序排列，然后只取昨天和前一天的值。比如：

CampaignReport::select(DB::raw('date(report_date) report_date', DB::raw('count(*) as count'))
    ->where('report_date','>=',$twoDaysAgo) 
    ->where('user_id', Auth::user()->id])
    ->groupBy('report_date')
    ->orderBy('report_date', 'desc');