【问题标题】:Laravel Calculate AVG of a related columnLaravel 计算相关列的 AVERAGE
【发布时间】:2017-09-10 19:19:42
【问题描述】:

我正在尝试计算相关列的平均评分。关系(1->many)在 Merchant 和 ClientFeedbackReviews 模型之间。

商家模式

[Merchant Model]
::::::::::::::::::::::::::::

public function clientFeedbacks() {
    return $this->hasMany('App\ClientFeedbackReviews'); //, 'merchant_id', 'id');

客户反馈评论

 ::::::::::::::::::::::::::::::::::::::: 

class ClientFeedbackReviews extends Model {

protected $table = 'client_feedback_merchants';
public function forMerchant() {
    return $this->belongsTo('App\Merchant', 'merchant_id', 'id');
}

public function byClient() {
    return $this->belongsTo('App\Clients', 'client_id', 'id');
}
:::::::::::::::::::::::::::::::::::::

我需要获得所有商家的平均评分(作为查询的一部分,我正在计算结果 - 商家根据附近的距离、给定的位置或根据请求数据使用的搜索字符串 em>)

我几乎尝试了在互联网上找到的所有内容,但无法在结果中获得“average_ratings”键值。

这是我尝试过的众多解决方案之一,并粘贴在这里作为示例

 /////// query continued //////////

 $getMerchantQuery = $getMerchantQuery->with(['clientFeedbacks' => function($query) {

            $query->select(DB::raw('AVG( stars) AS average_rating'));
        }]);

 /////// query continued //////////

这就是我得到的结果——client_feedbacks 的空数组,而我想要average_rating 就在那里。

  {
"id": 1,
"user_id": 2,
"company_name": "Best Salon",
"primary_contact": "111111111",
"company_st_address": "Office # 62",
"company_location": "Abc",
"company_city": null,
"company_state": null,
"company_country": null,
"company_zip": null,
"company_lat": "27.9506",
"company_long": "82.4572",
"logo_image": "449cbdf0-12ba-11e7-bc65-b7fa1731e4d5.jpeg",
"is_fav_by_client_count": 3,
"client_feedbacks_count": 1,
"user_details": {
  "id": 2,
  "email": "client@lir.com"
},
"client_feedbacks": []

}

我们有哪些选项可以计算相关表的平均值?

============ 编辑

但是这会返回结果,但不确定如何在 client_feedbacks 键中获取 AVERAGE。

      $getMerchantQuery = $getMerchantQuery->with('clientFeedbacks');

作为

{
"id": 1,
"user_id": 2,
"company_name": "Best Salon",
"primary_contact": "111111111",
"company_st_address": "Office # 62",
"company_location": "abc",
"company_city": null,
"company_state": null,
"company_country": null,
"company_zip": null,
"company_lat": "27.9506",
"company_long": "82.4572",
"logo_image": "449cbdf0-12ba-11e7-bc65-b7fa1731e4d5.jpeg",
"is_fav_by_client_count": 3,
"client_feedbacks_count": 1,
"user_details": {
  "id": 2,
  "email": "client@lbb.com"
},
"client_feedbacks": [
  {
    "id": 1,
    "client_id": 1,
    "merchant_id": 1,
    "stars": 4,
    "review_notes": "good client",
    "created_at": null,
    "updated_at": null
  }
]

}

【问题讨论】:

  • 已经快3天了还没有答案...

标签: laravel eloquent laravel-5.4 laravel-eloquent laravel-query-builder


【解决方案1】:

好的。所以这在blog 之后完成了工作:

    public function avgFeedback() {

    return $this->hasMany('App\ClientFeedbackReviews', 'merchant_id', 'id')
                    ->selectRaw('merchant_id,AVG(client_feedback_merchants.stars) AS average_rating')
                    ->groupBy('merchant_id');
}

public function getavgFeedbackAttribute() {
    // if relation is not loaded already, let's do it first
    if ($this->relationLoaded('commentsCount'))
        $this->load('avgFeedback');

    $related = $this->getRelation('avgFeedback');

    // then return the count directly
    return ($related) ? (int) $related->average_rating : 0;
}

我已经使用它如下:

    //////// query continued /////////

    $getMerchantQuery = $getMerchantQuery->with('avgFeedback');

    ///////  query continued //////////

【讨论】:

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