【发布时间】:2016-11-06 08:41:54
【问题描述】:
我正在尝试从 mac osx 上的 django 连接到 azure sql 服务。 当我关注时
from photo_mapper.models import Restaurant
rest_query = Restaurant.objects.all().query
print rest_query
SELECT [ate_it.restaurant].[id], [ate_it.restaurant].[name], [ate_it.restaurant].[area], [ate_it.restaurant].[city], [ate_it.restaurant].[submitter], [ate_it.restaurant].[pending], [ate_it.restaurant].[zid] FROM [ate_it.restaurant]
因此,当我做Restaurant.objects.all() 时,我得到了
Traceback (most recent call last):
File "<console>", line 1, in <module>
File "/Users/anubhav/workspace/ate-it/venv/lib/python2.7/site-packages/django/db/models/query.py", line 234, in __repr__
data = list(self[:REPR_OUTPUT_SIZE + 1])
File "/Users/anubhav/workspace/ate-it/venv/lib/python2.7/site-packages/django/db/models/query.py", line 258, in __iter__
self._fetch_all()
File "/Users/anubhav/workspace/ate-it/venv/lib/python2.7/site-packages/django/db/models/query.py", line 1074, in _fetch_all
self._result_cache = list(self.iterator())
File "/Users/anubhav/workspace/ate-it/venv/lib/python2.7/site-packages/django/db/models/query.py", line 52, in __iter__
results = compiler.execute_sql()
File "/Users/anubhav/workspace/ate-it/venv/lib/python2.7/site-packages/django/db/models/sql/compiler.py", line 848, in execute_sql
cursor.execute(sql, params)
File "/Users/anubhav/workspace/ate-it/venv/lib/python2.7/site-packages/django/db/backends/utils.py", line 79, in execute
return super(CursorDebugWrapper, self).execute(sql, params)
File "/Users/anubhav/workspace/ate-it/venv/lib/python2.7/site-packages/django/db/backends/utils.py", line 64, in execute
return self.cursor.execute(sql, params)
File "/Users/anubhav/workspace/ate-it/venv/lib/python2.7/site-packages/django/db/utils.py", line 95, in __exit__
six.reraise(dj_exc_type, dj_exc_value, traceback)
File "/Users/anubhav/workspace/ate-it/venv/lib/python2.7/site-packages/django/db/backends/utils.py", line 64, in execute
return self.cursor.execute(sql, params)
File "/Users/anubhav/workspace/ate-it/venv/lib/python2.7/site-packages/sql_server/pyodbc/base.py", line 538, in execute
return self.cursor.execute(sql, params)
ProgrammingError: ('42S02', "[42S02] [FreeTDS][SQL Server]Invalid object name 'ate_it.restaurant'. (208) (SQLExecDirectW)")
但是,当我使用 django.db.connections 手动运行查询 SELECT * from ate_it.restaurant 时,它运行良好。
我可以阻止 django 添加方括号吗?
我的数据库设置是
DATABASES = {
'default': {
'ENGINE': 'sql_server.pyodbc',
'NAME': 'mydatabase',
'USER' : 'myuser',
'PASSWORD' : 'mypwd',
'HOST' : 'myserver',
'PORT' : '1433',
}
}
我关注 this link 进行 freetds 和 unixodbc 设置
【问题讨论】:
-
您在 Python 和 Django 中使用什么包和版本?有几个;我猜 pyodbc==3.0.10,但是哪个 Django 包?
ate_it.restaurant是模式+表名的组合吗? -
我使用的是 Django 1.9.7。 ate_it 是架构,餐厅是表名
标签: python sql-server django pyodbc freetds