【发布时间】:2019-07-29 07:26:22
【问题描述】:
我如何/可以有选择地将数字传递给 Laravel 工厂,以便如果我不提供数字,它会执行默认操作,如果我提供,它会使用它们?
例如,我有一个Student 模型。它会生成一个随机的男性或女性学生,有 50% 的机会使用 Faker 的中间名,正如预期的那样。它看起来像这样:
$factory->define(App\Student::class, function (Faker $faker) {
$gender = $faker->randomElement($array = array ('m','f'));
$has_middle_name = $faker->boolean($chanceOfGettingTrue = 50);
$student = [];
if ($gender == 'm') {
$student['first_name'] = $faker->firstNameMale;
if ($has_middle_name) {
$student['middle_name'] = $faker->middleNameMale;
}
} else {
$student['first_name'] = $faker->firstNameFemale;
if ($has_middle_name) {
$student['middle_name'] = $faker->firstNameMale;
}
}
$student['last_name'] = $faker->lastName;
$student['gender'] = $gender;
$student['birth_date'] = $faker->dateTimeBetween($startDate = '-18 years', $endDate = '-4 years', $timezone = null);
return $student;
});
我已经看到我可以使用State 作为传递变量的一种方式。例如我可以这样做:
$student = factory(App\Student::class)->state('male')->make();
这将调用我工厂的这个位,因此修改first_name、middle_name 和gender 属性以与male 保持一致:
$factory->state(App\Student::class, 'male', function (Faker $faker) {
$student = [];
$student['first_name'] = $faker->firstNameMale;
$has_middle_name = $faker->boolean($chanceOfGettingTrue = 50);
if ($has_middle_name) {
$student['middle_name'] = $faker->middleNameMale;
}
$student['gender'] = 'm';
return $student;
});
但是,我上面的代码创建了一个 4 到 18 岁的学生。如果我想创建一个特定年龄的学生怎么办?我知道我可以这样做让学生在 8 到 9 岁之间:
$birth_date = $faker->dateTimeBetween($startDate = '-9 years', $endDate = '-9 years', $timezone = null);
$student = faker(App\Student::class)->make(['birth_date' => $birth_date]);
但我宁愿做这样的事情:
$student = faker(App\Student::class)->make($minAge = 8, $maxAge = 9);
这可能吗??
【问题讨论】: