discord.js Javascript字符串操作

Question

所以我正在创建一个带有 kick 命令的机器人，并希望能够为所述操作添加一个原因，我从某个地方听说我可能需要进行字符串操作。目前我有一个独立的原因，如下面的代码所示：

client.on("message", (message) => {
  // Ignore messages that aren't from a guild
  if (!message.guild) return;

  // If the message starts with ".kick"
  if (message.content.startsWith(".kick")) {
    // Assuming we mention someone in the message, this will return the user
    const user = message.mentions.users.first();
    // If we have a user mentioned
    if (user) {
      // Now we get the member from the user
      const member = message.guild.member(user);
      // If the member is in the server
      if (member) {
        member
          .kick("Optional reason that will display in the audit logs")
          .then(() => {
            // lets the message author know we were able to kick the person
            message.reply(`Successfully kicked ${user.tag}`);
          })
          .catch((err) => {
            // An error happened
            // This is generally due to the bot not being able to kick the member,
            // either due to missing permissions or role hierarchy
            message.reply(
              "I was unable to kick the member (this could be due to missing permissions or role hierarchy"
            );
            // Log the error
            console.error(err);
          });
      } else {
        // The mentioned user isn't in this server
        message.reply("That user isn't in this server!");
      }
      // Otherwise, if no user was mentioned
    } else {
      message.reply("You didn't mention the user to kick!");
    }
  }
});

Answer 1

我假设你希望你的完整命令看起来像

.kick @user Being hostile to other members

如果您想假设命令中未提及或“.kick”命令的所有内容都是原因，那么要从该字符串中获取原因，您可以执行一些简单的字符串操作来提取命令并从字符串中提及，并保留其他所有内容。

从未使用过 Discord API，但根据我从文档中拼凑出来的内容，这应该可以工作。

let reason = message.content.replaceAll(".kick", "")
message.mentions.forEach((mentionedUser) => reason.replaceAll("@" + mentionedUser.username, "")
// assume everything else left in `reason` is the sentence given by the user as a reason

if (member) {
    member
      .kick(reason)
      .then(() => {
        // lets the message author know we were able to kick the person
        message.reply(`Successfully kicked ${user.tag}`);
      })
}

Answer 2

拆分 message.content 并切片前 2 个数组元素，这将为您留下构成原因的元素。将剩余的元素连接回一个字符串。

const user = message.mentions.users.first();
const reason = message.content.split(' ').slice(2).join(' ');

Answer 3

这里有一些帮助：

const args = message.content.slice(1).split(" "); //1 is the prefix length
const command = args.shift();
//that works as a pretty good command structure
if(command === 'kick') {
const user = message.mentions.users.first();
args.shift();
const reason = args.join(" ");
user.kick(reason);
//really close to Elitezen's answer but you might have a very terrible problem
//if you mention a user inside the reason, depending on the users' id, the bot could kick 
//the user in the reason instead!
}

以下是解决该问题的方法（使用正则表达式）

const userMention = message.content.match(/<@!?[0-9]+>/);
//you may have to do some more "escapes"
//this works since regex stops at the first one, unless you make it global
var userId = userMention.slice(2, userMention.length-1);
if(userId.startsWith("!")) userId = userId.slice(1);
const user = message.guild.members.cache.get(userId);
args.shift();
args.shift();
user.kick(args.join(" "))
.then(user => message.reply(user.username + " was kicked successfully"))
.catch(err => message.reply("An error occured: " + err.message))