为 ?members 命令显示昵称而不是用户名 (discord.js)

Question

这是我的代码

if (message.content.startsWith("?members")) {
        let roleName = message.content.split(" ").slice(1).join(" ");

        //Filtering the guild members only keeping those with the role
        //Then mapping the filtered array to their usernames
        let membersWithRole = message.guild.members.filter(member => {
            return member.roles.find(role => role.name.includes(roleName));
        }).map(member => {
            return member.user.username;
        })

        const embed = new Discord.RichEmbed({
            "title": `Members in ${roleName}`,
            "description": membersWithRole.join("\n"),
            "color": 0xFFFF

        });

        return message.channel.send(embed);



    }

我正在尝试使嵌入在服务器中显示人们的昵称，而不是他们不和谐的用户名。我试过 member.user.nickname，但它不起作用。任何帮助将不胜感激。

提前致谢！

Answer 1

您可以使用displayName。如果成员在服务器上没有特殊昵称，member.nickname 将返回 undefined。

最好先获取角色，然后映射角色成员。

if (message.content.startsWith("?members")) {
        let roleName = message.content.split(" ").slice(1).join(" ");

        //getRole
        let targetRole = message.guild.roles.find(role => role.name.includes(roleName))
        if(!targetRole) return message.channel.send('No role fined')
        let membersWithRole = targetRole.members.map(member => member.displayName) // Embed has max length so you need slice this array to pages if membersWithRole.join("\n").length > 2048

        const embed = new Discord.RichEmbed({
            "title": `Members in ${roleName}`,
            "description": membersWithRole.join("\n"),
            "color": 0xFFFF

        });

        return message.channel.send(embed);
    }