如何对 sql select 语句进行排序以便正确显示排行榜？

Question

我在选择和分组下表时遇到问题。 “Igralci”表如下所示：

----------------------------------------------
|ID|U_ID|st_tock|st_srecanj|st_nizov|st_gemov|
----------------------------------------------
|19| 17 |   6   |     3    |   6    |   72   |
----------------------------------------------
|11| 19 |  12   |     6    |   24   |   144  |
----------------------------------------------
|15| 18 |  12   |     6    |   26   |   72   |
----------------------------------------------

我想按以下方式对 id 进行排序：

1. First looks at st_tock (if st_tock is same) ->
2. Looks at st_srecanj (if st_srecanj is same) ->
3. Looks at st_nizov (if st_nizov is same) ->
4. Looks at st_gemov

我试过了：

Select * from Igralci 
group by id, st_tock, st_srecanj, st_nizov, st_gemov
order by st_tock, st_srecanj, st_nizov, st_gemov;

想要的显示将是（ID）：

1. 15（st_tock 和 st_srecanj 与 11 相同，但他有更多 st_nizov）
2. 11
3. 19

Answer 1

您需要在 order by 子句中添加“Desc”或“asc”以获得所需的结果。根据您提供的输出，您需要按顺序在每列后添加“Desc”

Select * from Igralci 
group by id, st_tock, st_srecanj, st_nizov, st_gemov
order by st_tock desc, st_srecanj desc, st_nizov desc, st_gemov desc;