Python将变量从一个脚本发送到另一个答案

【问题标题】：Python send variable from one script to anotherPython将变量从一个脚本发送到另一个
【发布时间】：2014-01-25 04:46:33
【问题描述】：

大家好，我有关于在异常情况下将变量发送到另一个脚本的问题。脚本1.py：

def main():

    conn = None

    try:
        logging.basicConfig(level=logging.DEBUG, filename='{}'.format(error_log))

        try:
        #Define our connection string
            conn_string = ("host=x.x.x.x dbname=xxx user=xxx password=xxx")

            # Get a connection
            conn = psycopg2.connect(conn_string)

            # conn.cursor will return a cursor object
            cursor = conn.cursor()
            print "Connected to PostgreSQL!\n"



            root = open('x','rb').read() 
            p = root
            # Cursor insert into PostgreSQL XML as string
            cursor.execute("SELECT epg_insert_doc_xml_3(%s)",[str(p)])
            conn.commit()

        except psycopg2.DatabaseError, e:

            if conn:
                conn.rollback()
                print 'Error %s' % e 
                            var_x = 'Send some variable %s'% e
                logging.exception("Failed to process Datatbase error! %s" % e )   
                sys.exit(1)

    except:

        logging.exception("Failed to process Datatbase error! %s"% current_time)

    finally:

            if conn:
                conn.close()

if __name__ == "__main__":

    main()

我想将此脚本中的 var_x 发送到此脚本：脚本2.py

#!/usr/bin/python
# -*- coding: utf-8 -*-
import smtplib
import time
import pickle
from script1 import *

current_time = time.strftime("%Y/%m/%d %H:%M", time.localtime())

var = var_x

f = '{}  %s'.format(var_x) % current_time

class sendMail:

    def sendMessage(self):
        self.server = smtplib.SMTP('x', 25)
        self.server.login("x", "x")
        msg = "Opis greške:\n %s" % f 
        self.server.sendmail("x", "x", msg)

send = sendMail()
send.sendMessage()

但这不起作用，你能帮我解决这个问题吗？

【问题讨论】：

你想做什么，将数据发送到正在运行的script2 或使用参数执行script2？
是如果脚本1出现异常，调用script2.py并发送参数var_x。
哪个版本的python？ 3好不好？
python 2.7.3 是我的版本

标签： python email variables send

【解决方案1】：

您不会在脚本之间发送变量。您将 args 传递给函数 ...
您可以按如下方式修改脚本：

script2.py

#!/usr/bin/python
# -*- coding: utf-8 -*-
import smtplib
import time

class Mail:
    def send(self, var_x):
        current_time = time.strftime("%Y/%m/%d %H:%M", time.localtime())
        f = '{}  %s'.format(var_x) % current_time
        self.server = smtplib.SMTP('x', 25)
        self.server.login("x", "x")
        msg = "Opis greške:\n %s" % f 
        self.server.sendmail("x", "x", msg)

script1.py

from script1 import Mail  

def main():
    mail = Mail()
    ...
    mail.send(var_x)
    ...

【讨论】：

【解决方案2】：

试试这个：execfile("script2.py", {"var_x": var_x})

>>> help(execfile)
execfile(...)
    execfile(filename[, globals[, locals]])

    Read and execute a Python script from a file.
    The globals and locals are dictionaries, defaulting to the current
    globals and locals.  If only globals is given, locals defaults to it.

【讨论】：